小编sep*_*ehr的帖子

我想从src文件夹设置我的照片地址，并且基于vue doc我必须使用@。问题是，当我使用它时，jetbrains用红线在地址下划线，并且我的页面也不再编译，错误是：

Failed to compile.

./node_modules/css-loader?{"sourceMap":true}!./node_modules/vue-loader/lib/style-compiler?{"vue":true,"id":"data-v-7ba5bd90","scoped":false,"hasInlineConfig":false}!./node_modules/sass-loader/lib/loader.js?{"indentedSyntax":true,"sourceMap":true}!./node_modules/vue-loader/lib/selector.js?type=styles&index=0!./src/App.vue Module not found: Error: Can't resolve './@/assets/image/background.png' in '/home/sina/WebstormProjects/landing-vue/src' @ ./node_modules/css-loader?{"sourceMap":true}!./node_modules/vue-loader/lib/style-compiler?{"vue":true,"id":"data-v-7ba5bd90","scoped":false,"hasInlineConfig":false}!./node_modules/sass-loader/lib/loader.js?{"indentedSyntax":true,"sourceMap":true}!./node_modules/vue-loader/lib/selector.js?type=styles&index=0!./src/App.vue 7:749-791 @ ./node_modules/vue-style-loader!./node_modules/css-loader?{"sourceMap":true}!./node_modules/vue-loader/lib/style-compiler?{"vue":true,"id":"data-v-7ba5bd90","scoped":false,"hasInlineConfig":false}!./node_modules/sass-loader/lib/loader.js?{"indentedSyntax":true,"sourceMap":true}!./node_modules/vue-loader/lib/selector.js?type=styles&index=0!./src/App.vue @ ./src/App.vue @ ./src/main.js @ multi (webpack)-dev-server/client?http://localhost:8080 webpack/hot/dev-server ./src/main.js

这也是css：

background: url("@/assets/image/background.png");

在这个代码片段中我想将$ jsonArray卷曲到url并得到必须是代码的响应体但我的问题是它给我的唯一的东西是1(真)

$array = [
    "type"=>"send",
    "phone"=>"989107786584"
];
$jsonArray = json_encode($array);
$curl = curl_init();
curl_setopt($curl,CURLOPT_URL,'http://79.175.166.98/chargebazi/otp.php');
curl_setopt($curl,CURLOPT_POST,$jsonArray);
$result = curl_exec($curl);
$responseCode = json_decode($result);
echo $responseCode;

我想得到并提醒内容,input textbox但它无法正常工作有人可以帮助我吗？

$(document).ready(function() {
  var phoneField = $("#PhoneField").val();
  $("#SendPhone").click(function() {
    alert(phoneField);
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<fieldset>
  <h2 class="fs-title">Enter Your Number</h2>
  <h3 class="fs-subtitle">This is step 1</h3>
  <input type="text" name="email" placeholder="Phone number" id="PhoneField" />
  <input type="button" name="next" class="next action-button" value="Next" id="SendPhone" />
</fieldset>