我正在使用附加了Postgres DB Docker容器的Rails.我跑步时看起来好像遇到了以下错误rails c:
/usr/local/rvm/rubies/ruby-2.2.1/lib/ruby/2.2.0/uri/generic.rb:204:in `initialize': the scheme postgres does not accept registry part: postgres:@ (or bad hostname?) (URI::InvalidURIError)
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有没有理由不这样做?
我database.yml是:
production:
<<: *default
url: <%= ENV['DATABASE_URL'] %>
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$DATABASE_URL 被定义为
有趣的是,它一直工作到昨天,并且今天又停止了工作.
以下是Rails 4.2.1生成的内容!
# As with config/secrets.yml, you never want to store sensitive information,
# like your database password, in your source code. If your source code is
# ever seen by anyone, they now have access to your database.
#
# Instead, provide the password …Run Code Online (Sandbox Code Playgroud) 有没有办法在simple_form视图中显示多态关联?
到目前为止,我有以下内容:
= simple_form_for(@chat, :html => { :class => "form-horizontal" }, :wrapper => "horizontal", defaults: { :input_html => { class: "form-control"}, label_html: { class: "col-lg-4" } } ) do |f|
= f.error_notification
.form-inputs
= f.association :from_user
= f.association :to_user
= f.input :message
= f.association :chattable
.form-actions
= f.button :submit
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以下型号:
class Chat < ActiveRecord::Base
belongs_to :from_user, :foreign_key => 'from_user_id', class_name: 'User'
belongs_to :to_user, :foreign_key => 'to_user_id', class_name: 'User'
belongs_to :chattable, polymorphic: true
validates :from_user, associated: true, presence: true …Run Code Online (Sandbox Code Playgroud) 有没有办法使用
Rails link_to函数fa_icon(FontAwesome gem)
喜欢下面?
=link_to fa_icon("off"), destroy_user_session_path, :method=>'delete', {"data-toggle" => "tooltip", "data-original-title" => "Logout", "data-placement" => "bottom", :class => "btn btn-metis1 btn-sm"}
Run Code Online (Sandbox Code Playgroud) 我如何使用DISTINCT获取具有最高价值的唯一用户ID,total_time_driven_at_this_trip并user_name从另一个基于此关系的表中获取user_id?
我试过这个......
$this->set('tripNsws', $this->TripNsw->find('all',array('limit' => 20,'fields' => array('DISTINCT(TripNsw.user_id)','TripNsw.total_time_driven_at_this_trip'),'group' => array('TripNsw.user_id') ,'order' => array('TripNsw.total_time_driven_at_this_trip desc'))));
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但它不起作用.
我想你需要得到以下......
SELECT DISTINCT(user_id),`total_time_driven_at_this_trip` FROM `trip_nsws` order by `total_time_driven_at_this_trip` desc
Run Code Online (Sandbox Code Playgroud) 我在Wildfly 8.2中遇到错误:
05:17:12,202 INFO [org.jboss.msc] (main) JBoss MSC version 1.2.2.Final
05:17:12,285 INFO [org.jboss.as] (MSC service thread 1-6) JBAS015899: WildFly 8.2.0.Final "Tweek" starting
05:17:13,199 ERROR [org.jboss.as.controller.management-operation] (ServerService Thread Pool -- 12) JBAS014613: Operation ("add") failed - address: ([
("subsystem" => "datasources"),
("data-source" => "ExampleDS")
]) - failure description: "JBAS014803: Duplicate resource [
(\"subsystem\" => \"datasources\"),
(\"data-source\" => \"ExampleDS\")
]"
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我该如何删除重复的?
我在控制台上运行了以下命令
rails g migration payslips first_name:string last_name:string
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但这只是生成如下的空文件
class Payslips < ActiveRecord::Migration
def change
end
end
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我找不到原因.控制台生成命令有问题吗?
是否有整合的好方法hstore有simple_form?
我只是找不到实现这个目标的方法.我有一个调用的列widget_locations,我想将:left_area1, :mid_area1, :left_area2, :mid_area2, :right_area2键和值存储为嵌套的哈希,所以它们如下所示:
{:left_area1 => {:video_id => 1, :presentation_id => 3}, :mid_area1 => {:chat_id => 1, :presentation_id => 5}, :left_area2, :mid_area2, :right_area2}
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有没有一种在simple_form中实现这一目标的最佳方法?
有没有一种从CentOS 6.5安装最新cmake版本的好方法?
我正在做,yum install cmake但它给了我2.6.4基础回购,我不想要.
我尝试安装,cmake28但问题是,当我尝试这样做./configure会抛出一个错误,说cmake不可用.
我想在Cakephp中使用带有for循环的Save函数保存10次,但它似乎不起作用.它只保存一个数据.
我们如何才能在一次通话中保存多个数据呢?
以下是我的代码......
for($i=0;$i<10;$i++){
$unique_id = $this->_unique($userData['User']['id']); // Unique id with userid as initial prefix
$this->data['Invite'] = array('invited_user' => $userData['User']['id'], 'unique_id' => $unique_id);
$this->User->Invite->save($this->data['Invite']);
}
Run Code Online (Sandbox Code Playgroud) 是否有任何示例和/或方法可以在成功登录或注册凭据类型后重定向到私人仪表板next-auth?我找不到任何明确的文档。
我正在考虑在下面添加重定向,但不确定这是否是正确的方法:
callbacks.signIn = async (data, account, profile) => {
if ((account.provider === 'google' && profile.verified_email === true) || (account.type === 'credentials' && data.status === 200)) {
return Promise.resolve(true)
} else {
return Promise.resolve(false)
}
}
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