小编Hai*_* IT的帖子

我有这个示例代码:

<div id="click-test-1">Click test 1</div>
<div id="click-test-2">Click test 2</div>

在jQuery中我使用以下代码:

jQuery("div[id^=\'click-test\']").click(...);

如何在基本JavaScript中获得相同的功能？

<ul>
    <li>number</li> 
    <li>1</li>
    <li>2</li>
    <li>3</li>
    <li>4</li>
    <li>5</li>
</ul>

和样式表:

ul {
    list-style-type: none
}

ul li {
    float: left;
}

li:after {
    content: ", "
}

li:before {
    content: ": "
}

li:last-child:after {
    content: "."
}

li:first-child:before {
    content: ""
}

结果是:

number, 1, 2, 3, 4, 5.

如何解决这个问题:

number: 1, 2, 3, 4, 5.

我有一个示例代码:

<?php
$string = '07/01/2014'; // today format d/m/YY
echo date("m-d-Y", strtotime($string)); // result is 07-01-2014
?>

=>如何修复它的结果是01-07-2014今天的格式m-d-Y

我有一个样本

<h3>How to elasticity of the char length in javascript or css<h3>
<h3>How to elasticity<h3>

如果字符串很长,如何配置字符串的大小

<h3>How to elasticity of ...<h3>
<h3>How to elasticity<h3>

怎么样这个想法

可能重复:
警告:mysql_fetch_array():提供的参数不是有效的MySQL结果

在db.php我有:

<?php
class connect {

    private $host = "localhost";
    private $user = "root";
    private $pass = "";
    private $database = "databasename";
    private $connect = null;

    function connect() {
        $this->connect = mysql_connect($this->host, $this->user, $this->pass) or die("Can't connect database");
        mysql_select_db($this->database, $this->connect);
    }

    function getData() {
        $data = array();
        $sql = 'Select * From test';
        $query = mysql_query($sql);
        while($row = mysql_fetch_assoc($query)) {
            $data[] = array($row['id'], $row['name']);
        }
        return $data;
    }

}
?>

在index.php我有:

<?php
include 'db.php';
$connect = new connect();
$connect->connect(); …

我有一个代码PHP

foreach ($cities as $city) {
     echo substr($city->name . ", ", 0, -2);
}

结果是:a,b,c,d,e,

如何在foreach()中删除","

确切地说:a,b,c,d,e