小编kri*_*avi的帖子

我安装的Apache Tomcat 6.0到一个C:/Program Files文件夹,我设置环境变量JAVA_HOME和CATALINA_HOME,但是当我使用启动服务器startup.bat,我得到的错误:

CATALINA_HOME环境变量未正确定义.

我的CATALINA_HOME环境变量设置为CATALINA_HOME=C:\Program Files\apache-tomcat-6.0.35.

我做错了什么？

你好.我在JSON中得到了输出...现在我需要将这些数据转换为javascript ..

如何在javascript中编写代码？我必须将图像显示到浏览器..只有通过在javascript中编写代码才有可能.帮我..

我的JSON输出是......

    [{"0":"101","member_id":"101","1":"3k.png","image_nm":"3k.png","2":"\/images\/phones\/","image_path":"\/images\/phones\/"},
     {"0":"102","member_id":"102","1":"mirchi.png","image_nm":"mirchi.png","2":"images\/phones\/","image_path":"images\/phones\/"},
     {"0":"103","member_id":"103","1":"masti.png","image_nm":"masti.png","2":"images\/phones\/","image_path":"images\/phones\/"}]

我已经在Ubuntu Natty上安装了星号，

当我进入星号CLI并输入sip reload或任何与SIP相关的命令时，它说未找到SIP命令

有人以前有过类似的问题吗？

谢谢

我必须向浏览器显示图像,我想从JSON响应中获取图像并使用Javascript将其显示给浏览器.这就是JSON响应的样子:

[{
    "0":"101",
    "member_id":"101",
    "1":"3k.png",
    "image_nm":"3k.png",
    "2":"\/images\/phones\/",
    "image_path":"\/images\/"
},{
    "0":"102",
    "member_id":"102",
    "1":"mirchi.png",
    "image_nm":"mirchi.png",
    "2":"images\/phones\/",
    "image_path":"images\/phones\/"
},{
    "0":"103",
    "member_id":"103",
    "1":"masti.png",
    "image_nm":"masti.png",
    "2":"images\/phones\/",
    "image_path":"images\/phones\/"
}]

我该怎么做(我是初学者)？

这是我写的代码...

       var jsonString =   '[{"0":"101","member_id":"101","1":"3k.png","image_nm":"3k.png","2":"\/images\/phones\/","image_path":"\/images\/phones\/"},{"0":"102","member_id":"102","1":"mirchi.png","image_nm":"mirchi.png","2":"images\/phones\/","image_path":"images\/phones\/"},{"0":"103","member_id":"103","1":"masti.png","image_nm":"masti.png","2":"images\/phones\/","image_path":"images\/phones\/"}]';
       var obj = JSON.parse(jsonString);

       for(var i = 0, len = obj.length; i < len; i++){
       var img = new Image();
       img.setAttribute("src",obj[i][2] + obj[i][1]);
       document.body.appendChild(img);
         }