小编Mic*_*arn的帖子

我正在学习c中的字符串.我使用code :: blocks作为编译器,即使它不仅仅用于c.因此,下面代码的问题是string2的输出是存储的5个字符加上string1的输出.我会给你看:

#include <stdio.h>
#include <string.h>          /* make strncpy() available */

int main()
{
char string1[]= "To be or not to be?";
char string2[6];

/* copy first 5 characters in string1 to string2 */
strncpy (string2, string1, 5);

printf("1st string: %s\n", string1);
printf("2nd string: %s\n", string2);
return 0;
}

输出是:

1st string contains: To be or not to be? 
2nd string contains: To be To be or not to be?

如果你问我,那超过5个字符......

我正在接近Mike McGrath撰写的关于c编程的介绍性书籍的结尾,该书称为"简单的C编程".我想我会在本书之后通过外观来了解更多内容.无论如何,我正在使用内存分配,我编写了这个演示程序,但是当我尝试运行它时错误已关闭:

#include <stdio.h>
#include <stdlib.h>
int main()
{
    int i, *arr;

    arr = calloc(5, sizeof(int));
    if(arr!=NULL)
    {
        printf("Enter 5 integers, seperated by a space:");
        for(i=0; i<5; i++) scanf("%d", &arr[i]);
        printf("Adding more space...\n");
        arr = realloc(8, sizeof(int));
        printf("Enter 3 more integers seperated by a space:");
        for(i=5; i<8; i++) scanf("%d", &arr[i]);
        printf("Thanks.\nYour 8 entries were: ");
        for(i=0; i<8; i++) printf("%d, ", arr[i]);
        printf("\n");
        free(arr);
        return 0;
        }
    else {printf("!!! INSUFFICIENT MEMORY !!!\n"); return 1; }
}

警告信息:

|13|warning: passing argument 1 …