我无法在输出变量中搜索我用于when语句的指定字符串.下面的代码应该检查输出变量中的字符串"distribute-list",但是当运行playbook时它会给出错误.
fatal: [192.168.3.252]: FAILED! => {"failed": true, "msg": "The conditional check 'output | search(\"distribute-list\")' failed. The error was: Unexpected templating type error occurred on ({% if output | search(\"distribute-list\") %} True {% else %} False {% endif %}): expected string or buffer\n\nThe error appears to have been in '/home/khibiny/test4.yml': line 26, column 5, but may\nbe elsewhere in the file depending on the exact syntax problem.\n\nThe offending line appears to be:\n\n\n - debug:\n ^ here\n"}
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以下是导致问题的代码:
- ios_command:
commands: show run …Run Code Online (Sandbox Code Playgroud) 我想要一些有关具有多个条件的打印语句的语法的帮助。目前, for 的引号'{{inventory_hostname}}'导致错误,如果我删除引号,剧本会运行但会列出文本 inventory_hostname 而不是变量。我想知道如何打印变量,以及 if else 语句中的语法是否正确。
- debug:
msg: "{{ 'LTE status on '{{inventory_hostname}}' is good to go!' if output.stdout | join('') is search('Selected = LTE') else 'LTE status on '{{inventory_hostname}}' is not operational!' }}"
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