从我的MongoDB我想要等效的
SELECT column1, column2
FROM tbl
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使用此代码,我可以获得所有"行"以及所有"列"
DBCollection collection = database.getCollection("names");
DBCursor cursor = collection.find();
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例如,我想要所有 '行'但只有 '列':id,name,age
我该怎么做?
谢谢你的帮助!!
我有下面的代码有效:
if (aDBCursor.hasNext()) {
DBObject aDbObject = aDBCursor.next();
aDbObject.put("title", "Test Title");
ArrayList<DBObject> department = new ArrayList<DBObject>();
DBObject nested1 = new BasicDBObject();
nested1.put("name", "Department A");
nested1.put("id", 1);
department.add(nested1);
DBObject nested2 = new BasicDBObject();
nested2.put("name", "Department B");
nested2.put("id", 2);
department.add(nested2);
aDbObject.put("department", department);
collection.save(aDbObject);
}
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但是我在地图中有A部和B部的数据,如:
Map<Object,Object> map = new HashMap<Object,Object>();
map.put("1", "Department A");
map.put("2", "Department B");
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保存这些数据的最佳/最简单方法是什么?有没有办法将地图直接放入mongo DB?或者我是否必须在地图上循环?
进入地图的数据已经从数据库中获取,如下所示:
String[] values = req.getParameterValues("departments");
Map<Object,Object> map = new HashMap<Object,Object>();
DBCollection collection = database.getCollection("Departments");
BasicDBObject query = new BasicDBObject();
query.put("id", new BasicDBObject("$in", values));
DBCursor …Run Code Online (Sandbox Code Playgroud) 我试图从这个JSON字符串中获取值,但我很难实现这一点.
{"DebugLogId":"1750550","RequestId":"17505503","Result":
{"Code":"","DebugLogId":"1750550","Message":""},
"Suggestions":[
{"Ranking":"1","Score":"60","Title":"This is a test message 1"},
{"Ranking":"2","Score":"60","Title":"This is a test message 2"}
]}
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在"建议"中访问数据最简单的方法是什么?我正在使用GSON模块.理想情况下,我想把它全部放在HashMap中.
感谢您的帮助和/或建议!
谢谢你的帮助!
我有一个MongoDB,我希望获得两条记录或更多记录并将其放入地图中.如果我只有一个代码,则下面的代码可以正常query.put(ïd", "7");工作,但如果我在下面的代码中添加两个或更多代码,则代码不起作用.
Map<Object,Object> map= new HashMap<Object,Object>();
DBCollection collection = database.getCollection("Members");
BasicDBObject query = new BasicDBObject();
query.put("id", "7");
query.put("id", "3");
DBCursor cursor = collection.find(query);
DBObject one;
while(cursor.hasNext()) {
one = cursor.next();
map.put(one.get("id"),one.get("name"));
}
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如何在地图上获得两条或更多条记录?对于SQL,等价物将是SELCT * FROM Member WHERE id = 7 AND id = 3
更完美的是,如果我可以将列表作为查询,不确定这是否可行.