我正忙于制作语音识别代码，我有这个：

from pocketsphinx.pocketsphinx import *
from sphinxbase.sphinxbase import *

import os
import pyaudio
import wave
import audioop
from collections import deque
import time
import math

 class SpeechDetector:
     def __init__(self):
        self.CHUNK = 1024
        self.FORMAT = pyaudio.paInt16
        self.CHANNELS = 1
        self.RATE = 16000

        self.SILENCE_LIMIT = 1
        self.PREV_AUDIO = 0.5

        self.THRESHOLD = 4500
        self.num_phrases = -1

        MODELDIR = "../../tools/pocketsphinx/model"
        DATADIR = "../../tools/pocketsphinx/test/data"

        config = Decoder.default_config()
        config.set_string('-hmm', os.path.join(MODELDIR, 'en-us/en-us'))
        config.set_string('-lm', os.path.join(MODELDIR, 'en-us/en-us.lm.bin'))
        config.set_string('-dict', os.path.join(MODELDIR, 'en-us/cmudict-en-us.dict'))

        self.decoder = Decoder(config)

    def setup_mic(self, num_samples=50):
        print "Getting intensity …

我正在尝试制作一个使用语音识别的程序。现在，我遇到了一个问题，那就是您必须按下按钮或Enter才能启动语音识别。您是否可以说出一个短语（类似于Hey Google）来开始识别Python 3中的语音？
这是我的代码：

录制音频代码：

r = sr.Recognizer()

with sr.Microphone() as source:
    audio = r.listen(source)
x = r.recognize_google(audio)

print("I'm listening!")

try:
    print("You said: " + r.recognize_google(audio))
except speech_recognition.UnknownValueError:
    print("I am sorry but I couldn't understand you, try again.")
except speech_recognition.RequestError as e:
    print("Could not request results from Google Speech Recognition service; {0}".format(e))

提前致谢！