小编JPG*_*JPG的帖子

我正在学习Django REST Framework。我想在django rest框架中使用django-filter选择我想要的结果。我写了一个filter.py来获取价格在pricemin和pricemax之间的商品：

class GoodsFilter(filters.FilterSet):
    pricemin = filters.NumberFilter(name="shop_price", lookup_expr='gte')
    pricemax = filters.NumberFilter(name="shop_price", lookup_expr='lte')

    class Meta:
        model = Goods
        fields = ['pricemin', 'pricemax']

然后我在view.py中使用了此过滤器：

class GoodsListViewSet(mixins.ListModelMixin,viewsets.GenericViewSet):
    queryset = Goods.objects.all()
    serializer_class = GoodsSerializer
    pagination_class = GoodsPagination
    filter_backends = (DjangoFilterBackend,)
    filter_class = GoodsFilter

当我运行项目时，会出现如下错误：

TypeError at /goods/
__init__() got an unexpected keyword argument 'name'

我没有在代码中使用参数'name'，所以我不知道该错误。追溯：

Environment:


Request Method: GET
Request URL: http://127.0.0.1:8000/goods/

Django Version: 2.0.3
Python Version: 3.6.4
Installed Applications:
['django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'DjangoUeditor',
 'users.apps.UsersConfig',
 'goods.apps.GoodsConfig',
 'trade.apps.TradeConfig',
 'user_operation.apps.UserOperationConfig',
 'crispy_forms', …

这是我的models.py

from __future__ import unicode_literals
from django.db import models

class User(models.Model):
    name = models.CharField(max_length=200)
    company_name = models.ForeignKey('Company',on_delete=models.CASCADE,related_name='user')

    def __str__(self):
        return self.name

class Company(models.Model):
    name = models.CharField(max_length=200)
    phone_number = models.IntegerField(null=True,blank=True)

    def __str__(self):
        return self.name

class Catalog(models.Model):
    name = models.CharField(max_length=200)
    no_of_pcs = models.IntegerField(null=True,blank=True)
    per_piece_price = models.DecimalField(null=True,blank=True,max_digits=10,decimal_places=2)
    company_name = models.ForeignKey(Company,on_delete=models.CASCADE,related_name='catalog')

    def __str__(self):
        return self.name

这是我的 serializers.py

from rest_framework import serializers
from .models import *
from django.db.models import Sum,Count

class UserSerializer(serializers.ModelSerializer):
    # name = serializers.StringRelatedField()
    # company_name = serializers.CharField()
    class Meta:
        model = User …

我正在尝试使用 django-graphene 返回过滤结果，但它给出了有关错误消息的错误

class PatientType(DjangoObjectType):
    class Meta:
        model = Patients
        exclude = ('active',)
        interfaces = (relay.Node,)


class PatientsQuery(ObjectType):
    get_patient = graphene.Field(PatientType, id=graphene.Int())
    all_patients = graphene.List(
        PatientType, first=graphene.Int(), skip=graphene.Int(), phone_no=graphene.Int()
    )
    upcoming_appointments = DjangoFilterConnectionField(PatientType)


@permissions_checker([IsAuthenticated, CheckIsOrganizationActive])
def resolve_upcoming_appointments(self, info, **kwargs) -> List:
    d = datetime.today() - timedelta(hours=1)
    settings.TIME_ZONE  # 'Asia/Karachi'
    aware_datetime = make_aware(d)
    res = Patients.objects.filter(appointments__booking_date__gte=aware_datetime,
                                  appointments__booking_date__day=aware_datetime.day,
                                  appointments__status=True)
    if res:
        return res
    return []


class Query(
    organization_schema.OrganizationQuery,
    inventory_schema.MedicineQuery,
    patient_schema.PatientsQuery,
    graphene.ObjectType,
):
    pass

考虑到我有一个简单的观点，

# serializers.py
class EmptyPayloadResponseSerializer(serializers.Serializer):
    detail = serializers.CharField()


# views.py
from rest_framework.views import APIView
from rest_framework.response import Response
from drf_spectacular.utils import extend_schema
from .serializers import EmptyPayloadResponseSerializer


class EmptyPayloadAPI(APIView):
    @extend_schema(responses=EmptyPayloadResponseSerializer)
    def post(self, request, *args, **kwargs):
        # some actions
        return Response(data={"detail": "Success"})

当我渲染架构时，我收到以下错误响应，

错误#0：EmptyPayloadAPI：无法猜测序列化程序。这是 APIView 的优雅后备处理。如果视图在您的控制之下，请考虑使用 GenericAPIView 作为视图基类。暂时忽略视图。

那么，我如何告诉@extend_schema装饰器我不打算传递任何内容作为有效负载？

有什么办法可以使用两个不同的邮箱地址通过SSH Key操作GitLab和GitHub账户吗？