我有这个gulpfile.js文件:
var gulp = require('gulp'),
sass = require('gulp-sass'),
uglify = require('gulp-uglify'),
concat = require('gulp-concat'),
browserSync = require('browser-sync').create();
gulp.task('sass', function() {
gulp.src('assets/src/sass/*.scss')
.pipe(sass())
.pipe(gulp.dest('assets/dist/css'))
.pipe(browserSync.stream());
});
gulp.task('scripts', function() {
gulp.src('assets/src/js/*.js')
.pipe(concat('main.js'))
.pipe(uglify())
.pipe(gulp.dest('assets/dist/js'));
});
gulp.task('server', ['sass','scripts'], function() {
browserSync.init({
proxy: 'http://localhost/example/',
});
gulp.watch('assets/src/sass/*.scss', ['sass']);
gulp.watch('assets/src/js/*.js', ['scripts']);
gulp.watch('./**/*.php').on('change', browserSync.reload);
});
gulp.task('server', ['run']);
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请告诉我有什么区别:
.pipe(browserSync.stream());
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和:
gulp.watch('./**/*.php').on('change', browserSync.reload);
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我需要他们两个?他们有不同的角色?
谢谢.