小编aCm*_*SQL的帖子

我不明白这个错误.

我使用codeigneter和Jquery&ajax

Error parsererror

personEdit.php

$(document).ready(function(){
    var options = {
        dataType :      'json',
        beforeSubmit:   saveShowRequest, // pre-submit callback
        success:        saveShowResponse,  //post-submit callback
        error: function (xhr, ajaxOptions, thrownError){
            //alert('Error !!'++ xhr.statusText);

            //alert(thrownError);
            $('#output_test').html('<h2>Error !!!!: ' + xhr.statusText +'</h2>'+thrownError );
        } 

        // other available options: 
        //url:       url         // override for form's 'action' attribute
        //type:      type        // 'get' or 'post', override for form's 'method' attribute 
        //dataType:  null        // 'xml', 'script', or 'json' (expected server response type) 
        //clearForm: true        // clear all form fields …