小编tro*_*tro的帖子

我有一个关于并行循环的问题.我有以下代码:

    public static void MultiplicateArray(double[] array, double factor)
    {
        for (int i = 0; i < array.Length; i++)
        {
            array[i] = array[i] * factor;
        }
    }

    public static void MultiplicateArray(double[] arrayToChange, double[] multiplication)
    {
        for (int i = 0; i < arrayToChange.Length; i++)
        {
            arrayToChange[i] = arrayToChange[i] * multiplication[i];
        }
    }

    public static void MultiplicateArray(double[] arrayToChange, double[,] multiArray, int dimension)
    {
        for (int i = 0; i < arrayToChange.Length; i++)
        {
            arrayToChange[i] = arrayToChange[i] * multiArray[i, dimension];
        }
    }

现在我尝试添加并行功能: …

我想计算两个地理点的距离.这些点以经度和纬度给出.

坐标是:

第1点:36.578581,-118.291994

第2点:36.23998,-116.83171

这里有一个网站来比较结果:

http://www.movable-type.co.uk/scripts/latlong.html

这里是我从这个链接使用的代码: 计算谷歌地图V3中两点之间的距离

    const double PIx = Math.PI;
    const double RADIO = 6378.16;

    /// <summary>
    /// Convert degrees to Radians
    /// </summary>
    /// <param name="x">Degrees</param>
    /// <returns>The equivalent in radians</returns>
    public static double Radians(double x)
    {
        return x * PIx / 180;
    }

    /// <summary>
    /// Calculate the distance between two places.
    /// </summary>
    /// <param name="lon1"></param>
    /// <param name="lat1"></param>
    /// <param name="lon2"></param>
    /// <param name="lat2"></param>
    /// <returns></returns>
    public static double DistanceBetweenPlaces(double lon1, double lat1, …