小编Rit*_*tta的帖子

我正在关注railstutorial.org教程我收到以下错误

  1) User pages signup with valid information should create a user
     Failure/Error: fill_in "password" , with: "foobar"
     Capybara::ElementNotFound:
       cannot fill in, no text field, text area or password field with id, name, or label 'password' found
     # (eval):2:in `fill_in'
     # ./spec/requests/user_pages_spec.rb:32:in `block (4 levels) in <top (required)>'

  2) Authentication signin with invalid information 
     Failure/Error: before { click_button "Sign in" }
     Capybara::ElementNotFound:
       no button with value or id or text 'Sign in' found
     # (eval):2:in `click_button'
     # ./spec/requests/authentication_pages_spec.rb:14:in `block (4 …

我在代码中创建了一个具有以下架构的表

DB.create_table :Pokemon do
  primary_key :id
  String :first_name
  String :last_name
  String :email
  String :zipcode
  String :company_name
  String :google_profile
  String :skype
  String :phone
  String :about
  String :linkedin_profile_url
  String :company_url
  column :needs , 'Text[]'
  column :offering , 'Text[]'
end

为了需求和提供，我插入了一个带有以下代码的字符串数组

pokes=DB[:Pokemon];
off=['hello1' , 'hello2']
nee= ['need1' , 'need2']
pokes.insert(:first_name => 'abcd' ,:last_name => 'mehandiratta', :offering => off , :needs =>  nee)

当我运行它时出现错误

PG::Error: ERROR:  column "offering" is of type text[] but expression is of type record (Sequel::DatabaseError)
LINE 1: ...fering", "needs") VALUES …

您好我在此代码/*类中收到以下错误:CreateMobileChatterCntrl说明:联系人发布Chatter.开发者:Harish Khatri(Appirio Offshore)创建日期:2012年6月2日*/

public without sharing class CreateMobileChatterCntrl {
  public final Id ContactID{get;set;}
  public String message{get;set;}
  public boolean isSuccess{get;set;}
  public boolean throwError{get;set;}
  public String deviceType{get;set;}
  //----------------------------------------------------------------------------    
    //constructor
  //----------------------------------------------------------------------------  
  public CreateMobileChatterCntrl() {
    throwError = false;
    isSuccess = false;
    if( ApexPages.CurrentPage().getParameters().get('id') != null){
      ContactID = ApexPages.CurrentPage().getParameters().get('id');
    }
    String userAgent = ApexPages.currentPage().getHeaders().get('USER-AGENT');
    if(userAgent.contains('iPhone')) 
      deviceType = 'iPhone';
    //else if(userAgent.contains('Android')) deviceType = 'Android';  
  }
  //----------------------------------------------------------------------------    
    // Post the chatter on contact
  //----------------------------------------------------------------------------
  public Pagereference save() {

    if(message == null || message ==''){
      throwError = true; …

我收到以下错误

错误:编译错误:实体'Lead'上没有此列"所有者".如果您尝试使用自定义字段,请务必在自定义字段名称后附加"__c".请参考您的WSDL或描述调用以获取适当的名称.在第8栏第17栏

trigger Lead_Assignment on Lead (after insert) {

     List<Lead> le=trigger.new;
     User us=le.get(0).CreatedBy;
    List<User> u=[SELECT id from USER WHERE At_Work__c=true];    
    List<integer> ii=new List<Integer>();
    for(User uu:u){
    Integer xx= [SELECT count() from Lead WHERE Owner=:uu];


    }



}

在Lead对象中有一个名为Owner的字段为什么我收到此错误请帮助解决此错误.

我正在构建一个visualforce页面我必须在pageblocksectionitem中创建一个visualforce页面,就像我在我的代码中显示的那样.我不太了解css.我的代码是

<apex:page standardController="Account">
<apex:pageBlock title="My Content">
<apex:pageBlockSection>
<apex:pageBlockSectionItem>
<apex:pageBlockTable value="{!account.Contacts}" var="item">
<apex:column value="{!item.name}"/>
</apex:pageBlockTable>
</apex:pageBlockSectionItem>
</apex:pageBlockSection>
</apex:pageBlock>
</apex:page>

它显示的表格宽度小于屏幕宽度的一半.我不太了解css但是当我设置样式:{width:250%}然后它的宽度增加我必须设置多少百分比所以它的宽度将等于apex:pageblocktable没有被apex包围:blockSection和apex:pageBlockSectionItem或任何备用指南

我在正则表达式方面不擅长.我必须阅读一些文档很差的代码,任何人都可以告诉我这个正则表达式或代码行的含义是什么

myid.replace(/(:|\.)/g,'\\\\$1'); 

请告诉这个reg ex的意思??