当我尝试链接一个SIngleton类时得到
sources/singleton.cpp:8:41: error: no se puede declarar que la función miembro ‘static myspace::Singleton& myspace::Singleton::Instance()’ tenga enlace estático [-fpermissive]
sources/director.cpp:19:35: error: no se puede declarar que la función miembro ‘static void myspace::Singleton::Destroy()’ tenga enlace estático [-fpermissive]
myspace: *** [objects/singleton.o] Error 1
Singleton类:
#Singleton.h
#include <stdlib.h>
namespace myspace {
class Singleton
{
public:
static Singleton& Instance();
virtual ~Singleton(){};
private:
static Singleton* instance;
static void Destroy();
Singleton(){};
Singleton(const Singleton& d){}
};
}
#Singleton.cpp
#include "../includes/Singleton.h"
namespace myspace {
Singleton* Singleton::instance = 0;
static …我有一个存储库
class TurnoRepository extends EntityRepository
{
public function findTurnoActivo()
{
$q = $this
->createQueryBuilder('t')
->where('t.activo = :activo')
->setParameter('activo', true)
->getQuery();
return $q->getSingleResult();
}
}
抛出NoResultException但是如果我试图捕获我的控制器
private function obtenerTurno()
{
$em = $this->getDoctrine()->getEntityManager();
$turno = null;
try {
$turnoActivo = $em->getRepository('MyBundle:Turno')->findTurnoActivo();
} catch (NoResultException $e) {
return false;
}
return $turno;
}
我总是在我的页面上得到500内部服务器错误
我观察到,当我包括与模板ng-include的指令,ng-show并且ng-hide似乎没有工作.
注意:在angularjs 1.0.4和.中测试1.0.5
template.html<table ng-init="changeable = null">
<tr ng-repeat="(key, item) in items" ng-click="changeable = key">
<td>
<span ng-show="changeable != key">{{item.name}}</span>
<input ng-hide="changeable != key" ng-model="item.name">
</td>
<td>
<button ng-click="changeable = null">OK</button>
</td>
</tr>
</table>
template.html<div ng-include src="'/changeable_table.html'"></div>
changeable_table.html<table ng-init="changeable = null">
<tr ng-repeat="(key, item) in items" ng-click="changeable = key">
<td>
<span ng-show="changeable != key">{{item.name}}</span>
<input ng-hide="changeable != key" ng-model="item.name">
</td>
<td>
<button ng-click="changeable = null">OK</button>
</td> …我有一个带有自定义列表项的ListView
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="horizontal" >
<ImageView
android:id="@android:id/icon"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:contentDescription="@string/app_name"
android:maxWidth="32dp" />
<TextView
android:id="@android:id/title"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_gravity="center|left"
android:paddingBottom="4dp"
android:paddingTop="4dp"
android:textIsSelectable="true"
android:textSize="24sp" >
</TextView>
</LinearLayout>
现在Eclipse警告我This tag and its children can be replaced by one <TextView/> and a compound drawable.一切正常,但我讨厌警告,现在我改变了观点.
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="horizontal" >
<TextView
android:id="@android:id/title"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_gravity="center|left"
android:paddingBottom="4dp"
android:paddingTop="4dp"
android:textIsSelectable="true"
android:textSize="24sp"
android:drawableLeft="@drawable/unstarred" >
</TextView>
</LinearLayout>
但是图像没有显示,可以告诉我布局有什么问题,这是我的适配器
public class CategoryAdapter extends ArrayAdapter<Category> {
private Context mContext;
private int …我有一个具有以下结构的项目
/cmake_modules/
FindSFML.cmake
/includes/
car.hpp
motor.hpp
tires.hpp
/sources/
car.cpp
motor.cpp
tires.cpp
/main.cpp
/main.hpp
我有以下CMakeFiles.txt文件：
cmake_minimum_required(VERSION 2.8)
project (MYGAME)
set (MYGAME_VERSION_MAJOR 1)
set (MYGAME_VERSION_MINOR 0)
set (EXECUTABLE_NAME "mygame")
include_directories ("${MYGAME_BINARY_DIR}")
include_directories ("${MYGAME_BINARY_DIR}/includes")
link_directories ("${MYGAME_BINARY_DIR}/sources")
add_executable(${EXECUTABLE_NAME} main.cpp)
set(CMAKE_MODULE_PATH "${CMAKE_SOURCE_DIR}/cmake_modules" ${CMAKE_MODULE_PATH})
find_package(SFML 2.0 REQUIRED system window graphics network audio)
target_link_libraries(${EXECUTABLE_NAME} ${SFML_LIBRARIES})
当我尝试执行时make，得到以下信息：
[100%] Building CXX object CMakeFiles/mygame.dir/main.cpp.o
Linking CXX executable mygame
CMakeFiles/mygame.dir/main.cpp.o: In function `main':
main.cpp:(.text+0x11): undefined reference to `mynamespace::Car::Instance()'
main.cpp:(.text+0x21): undefined reference to `mynamespace::Car::start()'
collect2: error: ld returned …目前，如果我想附加绑定，我会这样做
DataBindingUtil.setContentView(this, R.layout.main_activity);
我遇到了需要调用的自定义第三方活动的问题
setContentView(R.layout.main_activity);
如何将绑定附加到设置了布局的活动 setContentView
我最近使用Firebase实现了一个基本应用程序,按照教程,做了一些事情,我将我的应用程序部署到其他人,然后我只是阅读清单,我发现我没有任何权限.这怎么可能？
在我的模型中,我有
/**
* @ORM\Entity
* @ORM\HasLifecycleCallbacks()
*/
class Terrain
{
/**
* @var lots
*
* @ORM\OneToMany(targetEntity="Lot", mappedBy="terrain")
*/
private $lotes;
/**
* @ORM\PreRemove
*/
public function deleteAllLots()
{
$lots = $this->getLots();
foreach ($lots as $lot) {
$this->lots->removeElement($lot);
}
}
}
/**
* @ORM\Entity
* @ORM\HasLifecycleCallbacks()
*/
class Lot
{
/**
* @var Terrain
*
* @ORM\ManyToOne(targetEntity="Terrain", inversedBy="lots")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="terrain_id", referencedColumnName="id")
* })
*/
var $terrain
}
批量
我正在尝试删除地形,但之前我删除了与之相关的所有批次.当我尝试删除地形时,我收到一个错误SQLSTATE[23000]: Integrity constraint violation
如何从中添加ICommand事件FrameworkElement？
具体来说,我想做以下几点
<ListView> <!-- Button, Windows or whatever element -->
<my:EventToCommand
Name="PreviewMouseLeftButton"
Command="{Binding Path=MyCommand}"
CommandParameter="{Binding ...}" />
<!-- Value, Element, etc.. -->
</ListView>
我想实现我自己的解决方案,这是出于教育目的,我不希望使用任何第三方库(MVVM Light,Prism等)
我有一个实体
Product:
name # string
country # entity
categories #entity many-many
我有一个该实体的表格
ProductType:名称类别
现在我需要按国家/地区筛选类别,但我不想在我构建表单时显示国家/地区参数
//...
$entity = new Entity\Product();
$entity->setCountry($this->getUser()->getProfile()->getCountry());
$form = $this->createForm(new Form\ProductType(), $entity);
return array('form' => $form->createView());
我希望在ProductType类中按国家/地区筛选类别,如何实现此目的？
我如何将$ country值传递给查询构建器？
//...
->add('categories', 'entity', array(
'class' => 'MyBundle:Category',
'query_builder' => function(EntityRepository $er) {
return $er->createQueryBulder('c');
}
)