小编MRi*_*izq的帖子

首先,我阅读文档如下

http://download.oracle.com/javase/1.4.2/docs/api/java/util/regex/Pattern.html

我希望找到任何标点字符,除了@',但我不太明白.

这是 :

public static void main( String[] args )
{       
     // String to be scanned to find the pattern.
     String value = "#`~!#$%^";
     String pattern = "\\p{Punct}[^@',&]";

    // Create a Pattern object
    Pattern r = Pattern.compile(pattern, Pattern.CASE_INSENSITIVE);

    // Now create matcher object.
    Matcher m = r.matcher(value);
    if (m.find()) {
       System.out.println("Found value: " + m.groupCount());
    } else {
       System.out.println("NO MATCH");
    }


}

结果没有比赛.
有什么不匹配的吗？

谢谢
MRizq

我已经生成了html，我需要使用Jquery重构html，如下所示：

原版的：

<table id="myTableID">
<tr id="tr01">
    <td>Col 1 Value</td>
</tr>
<tr id="tr02">
    <td>Col 2 Value</td>
</tr>
<tr id="tr03">
    <td>Col 3 Value</td>
</tr>
<tr id="tr04">
    <td>Col 4 Value</td>
</tr>
</table>

预期：

<table id="myTableID">
<tr id="tr01">
    <td>Col 1 Value</td>
    <td>Col 2 Value</td>
</tr>
<tr id="tr02">
    <td>Col 3 Value</td>
    <td>Col 4 Value</td>
</tr>
<tr id="tr03">
</tr>
<tr id="tr04">
</tr>
</table>

var tableNew = "<table id='myTableID'>"+
       "<tr><td>new "+
       "</td></tr>"+
       "</table>";

       $('#myTableID').replaceWith(tableNew);

我想出了迭代和替换的想法，还有更好的主意吗？

我正在谷歌搜索如何在没有运气的情况下将CHAR转换为DB2 iSeries中的TIMESTAMP,你能帮助我吗？

例如:20120216

预期成果:16/2/2012 12:00:00 AM

我的UDF:

CREATE FUNCTION TEST.CONVERT_TO_TIMESTAMP (VAL CHARACTER VARYING(20))
RETURNS TIMESTAMP
LANGUAGE SQL
SPECIFIC TEST.CONVERT_TO_TIMESTAMP
MODIFIES SQL DATA
CALLED ON NULL INPUT
FENCED
DISALLOW PARALLEL
NO EXTERNAL ACTION
BEGIN ATOMIC
DECLARE SQLCODE INTEGER DEFAULT 0 ;
DECLARE RETCODE INTEGER DEFAULT 0 ;
DECLARE RET TIMESTAMP ;
DECLARE CONTINUE HANDLER FOR SQLEXCEPTION , SQLWARNING , NOT FOUND
BEGIN
SET RETCODE = SQLCODE ;
END ;

IF ( VAL IS NOT NULL ) THEN
SET RET = CAST …