考虑这个递归的多线程程序:
#include <iostream>
#include <thread>
#define NUMTHREADS 4
using namespace std;
int g[NUMTHREADS];
thread t[NUMTHREADS];
void task1(int x)
{
if(x+1<NUMTHREADS)
t[x] = thread(task1, x+1);
for(int i=0;i<100000000;i++)
g[x]++;
if(x+1<NUMTHREADS)
t[x].join();
}
int main()
{
task1(0);
for(int i=0;i<NUMTHREADS;i++)
cout<<g[i]<<" ";
}
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我期望线程开销是微不足道的,但事实上程序的运行时间随着线程数的增加呈线性增长.
这是我的6核cpu的一些时间:
NUMTHREADS = 1:
$ time ./a
100000000
real 0m0.330s
user 0m0.312s
sys 0m0.015s
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NUMTHREADS = 2:
$ time ./a
100000000 100000000
real 0m0.742s
user 0m1.404s
sys 0m0.015s
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NUMTHREADS = 3:
$ time ./a
100000000 100000000 100000000
real 0m1.038s
user …Run Code Online (Sandbox Code Playgroud)