小编Onu*_*bek的帖子

我正在构建一个简单的待办事项列表应用程序.我试图通过将它们相对于彼此定位来组织我的布局.我通过调用XML属性来做到这一点android:layout_toStartOf="@id/to_do_btn"但是我收到了一个No Resource Found That Matches The Given Name错误.我基本上尝试了Stackoverflow上的每个解决方案但没有任何帮助.这是我的XML:

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
    xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    tools:context="myapp.onur.todo.MainActivity">

    <ListView
        android:id="@+id/to_do_list"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_alignParentTop="true"
        android:layout_alignParentStart="true"
        android:layout_above="@id/to_do_btn"
        android:layout_margin="5dp"
        >
    </ListView>

    <EditText
        android:id="@+id/to_do_editText"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:hint="Enter Something To Do"
        android:layout_toStartOf="@id/to_do_btn"
        android:layout_alignParentBottom="true"
        android:layout_alignParentStart="true"
        android:layout_alignTop="@id/to_do_btn"
        android:layout_below="@id/to_do_list"
        android:layout_margin="5dp"
        />

    <Button
        android:id="@+id/to_do_btn"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="add item"
        android:layout_margin="5dp"
        android:layout_alignParentBottom="true"
        android:layout_alignParentEnd="true"
        />

</RelativeLayout>

这是错误的一个例子: Error:(15, 31) No resource found that matches the given name (at 'layout_above' with value '@id/to_do_btn').

我不知道是怎么回事.如果它有帮助,这是我的gradle依赖项:

dependencies {
    compile fileTree(include: ['*.jar'], dir: …

我正在尝试用C++构建Bulls&Cows游戏.我已经实现了大部分逻辑.游戏使用无限循环连续运行,并在每次运行时生成随机值.

我现在要做的是现在是输入用户输入并在输入有效时运行代码(只能是4位整数).这是我的实施:

#include ...

using namespace std;

vector<int> getDigits(int modelValue) {
    vector<int> vectorValue;
    int extractedDigit = 0;
    int modulant = 10000;
    int divisor = 1000;

    for (int i = 0; i < 4; i++) {
        extractedDigit = (modelValue % modulant) / divisor;
        vectorValue.push_back(extractedDigit);
        modulant /= 10;
        divisor /= 10;
    }return vectorValue;
}


int main() {
    for (;;) {
        int model = rand() % 9000 + 1000;
        int guess = 0000;
        int bulls = 0;
        int cows = 0;
        int counter …

我正试图解决Kaggle的泰坦尼克号生存计划.这是我实际学习机器学习的第一步.我有一个问题,性别列导致错误.堆栈跟踪说could not convert string to float: 'female'.你们是怎么遇到这个问题的？我不想要解决方案.我只是想要一个实用的方法解决这个问题,因为我确实需要性别列来构建我的模型.

这是我的代码:

import pandas as pd
from sklearn.tree import DecisionTreeRegressor
from sklearn.model_selection import train_test_split
from sklearn.metrics import mean_absolute_error

train_path = "C:\\Users\\Omar\\Downloads\\Titanic Data\\train.csv"
train_data = pd.read_csv(train_path)
columns_of_interest = ['Survived','Pclass', 'Sex', 'Age']
filtered_titanic_data = train_data.dropna(axis=0)

x = filtered_titanic_data[columns_of_interest]
y = filtered_titanic_data.Survived

train_x, val_x, train_y, val_y = train_test_split(x, y, random_state=0)

titanic_model = DecisionTreeRegressor()
titanic_model.fit(train_x, train_y)

val_predictions = titanic_model.predict(val_x)
print(filtered_titanic_data)

当我尝试python3 module_7.py在终端上运行时，出现以下错误：

  File "/opt/CarlaSimulator/PythonClient/live_plotter.py", line 227, in plot_figure
    tkagg.blit(photo, fca.get_renderer()._renderer, colormode=2)
AttributeError: module 'matplotlib.backends.backend_tkagg' has no attribute 'blit'

我检查了 matplotlib 安装，一切似乎都很好。使用CARLA模拟器时会出现此问题。有一些建议的修复方案，例如在 pyplot 导入之前添加 backend_tkagg 导入，但它没有解决问题。

我在本地运行我的笔记本以使用我自己的 GPU。与 Colab 不同，我在本地实例方面遇到了一些问题。当我运行这个单元格时：

np.random.seed(42)\ndata = ImageList.from_folder(path).split_by_rand_pct(valid_pct=0.2).label_from_re(pat=file_parse).transform(size=224).databunch()\n

I\xe2\x80\x99m 收到此错误：

/home/onur/.local/lib/python3.6/site-packages/torch/nn/functional.py:2854: UserWarning: The default behavior for interpolate/upsample with float scale_factor will change in 1.6.0 to align with other frameworks/libraries, and use scale_factor directly, instead of relying on the computed output size. If you wish to keep the old behavior, please set recompute_scale_factor=True. See the documentation of nn.Upsample for details. \n  warnings.warn("The default behavior for interpolate/upsample with float scale_factor will change "\n/home/onur/.local/lib/python3.6/site-packages/torch/nn/functional.py:2854: UserWarning: The default behavior for interpolate/upsample with …

我正在尝试使用 YOLOv5x 构建一个对象检测系统。我通过 Roboflow 网站创建了我的数据集，并将该数据集下载到我的笔记本后，我运行以下命令来开始训练：

!curl -L "https://app.roboflow.com/ds/[DATASET-LINK]" > roboflow.zip; unzip roboflow.zip; rm roboflow.zip

但我对每张图像都收到此错误：

train: WARNING: Ignoring corrupted image and/or label /content/yolov5/train/images/output_0446_png.rf.caced7dfbd9c68fe51180ceb8c2f04e8.jpg: duplicate labels
train: WARNING: Ignoring corrupted image and/or label /content/yolov5/train/images/output_0450_png.rf.808e3c83dd6b516900257848467d9a5b.jpg: duplicate labels
train: WARNING: Ignoring corrupted image and/or label /content/yolov5/train/images/output_0456_png.rf.898ad055d9c4cf67db7657c4901db2b7.jpg: duplicate labels
train: WARNING: Ignoring corrupted image and/or label /content/yolov5/train/images/output_0459_png.rf.8bc9567fac8542598a79c2bf11d4d8d5.jpg: duplicate labels
train: WARNING: Ignoring corrupted image and/or label /content/yolov5/train/images/output_0461_png.rf.62c902b73e1b6a92e1417b90c8dd3c9c.jpg: duplicate labels
train: WARNING: Ignoring corrupted image and/or label /content/yolov5/train/images/output_0462_png.rf.bf025028cd9eb5fe98d3cd80452a8d86.jpg: duplicate labels
train: WARNING: Ignoring corrupted image …

我在 Julia 中有这个 for 循环：

begin
    countries_data_labels = ["Canada", "Italy", "China", "United States", "Spain"]
    y_axis = DataFrame()
    
    
    for country in countries_data_labels
        
        new_dataframe = get_country(df, country)
        
        new_dataframe = DataFrame(new_dataframe)
        
        df_rows, df_columns = size(new_dataframe)
        
        new_dataframe_long = stack(new_dataframe, begin:end-4)
        
        y_axis[!, Symbol("$country")] = new_dataframe_long[!, :value]
        
    end
end

我收到此错误：

syntax: extra token ")" after end of expression

我决定注释除第一个循环之外的所有 for 循环体，并在取消注释后每次都运行单元格以查看哪一行抛出了这个错误，它是体中的第 4 行：

new_dataframe_long = stack(new_dataframe, begin:end-4)

没有理由存在此错误。该系列中没有额外的支架件。

这是来自图像的注释文件：

0 0.6142131979695431 0.336 0.467005076142132 0.392

第一个0是类标签。0.6142131979695431和0.336是边界框的 x 和 y 坐标。0.467005076142132和0.392是边界框的宽度和高度。但是，我不明白的是为什么 x、y、宽度和高度都在 [0,1] 浮点区间内。有人告诉我这是一个百分比，但是相对于什么的百分比呢？

例如，我正在编写构建合成数据集的软件。这是我制作的一张训练图像。它在我想要检测的对象周围有边界框。

边框完美地包裹了 Wizards 和 Ubuntu 徽标。那么，我该如何像上面的格式一样注释它们呢？

我正在执行leetcode，我的代码给了我我无法理解的错误。我被要求反转整数，这很容易做到。这些是测试用例：

Example 1:

Input: 123
Output: 321

Example 2:

Input: -123
Output: -321

Example 3:

Input: 120
Output: 21

我发现我所需要的只是if语句来检查输入的条件，所以这就是我所做的：

class Solution:
    def reverse(self, x: int) -> int:
        string = str(x)
        lst = list(string)

        lst.reverse()

        if((lst[0]) == '0'):
            lst.pop(0)

        if((lst[-1] == '-')):
            lst.pop(-1)
            lst.insert(0, '-')

        output = ''.join(lst)

        return output

但是这一行if((lst[-1] == '-')):抛出一个IndexError: list index out of range错误。我正在做的是访问列表的最后一个元素。我不尝试访问不存在的索引。

我唯一需要知道的是为什么会发生此错误。因为这是leetcode，所以我想自己修复该代码。

最终密码

class Solution:
    def reverse(self, x: int) -> int:
        lst = list(str(x))

        lst.reverse()

        if(x < 0):
            lst.pop(-1) …

我driving_log.csv为模拟器创建的每个图像的文件路径创建了一个 CSV 文件 ( )，但当时我使用的是我兄弟的 Windows 计算机，因此现在每个图像的文件路径如下所示（其中几乎有 14000 个图像）。从 my 调用它时出现错误file.py，该文件与 CSV 文件位于同一目录中。

C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\center_2020_02_08_14_16_38_988.jpg,C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\left_2020_02_08_14_16_38_988.jpg,C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\right_2020_02_08_14_16_38_988.jpg,0,0,0,7.918889E-06

我正在使用 Arch Linux。我想遍历每一行并将其更改为：

/home/onur/Documents/behavioral-cloning-CARLA/IMG/center_2020_02_08_14_16_38_988.jpg,left_2020_02_08_14_16_38_988.jpg,right_2020_02_08_14_16_38_988.jpg,0,0,0,7.918889E-06

正如你所看到的，我需要接下来的一切\IMG\。

解决这个问题的最佳方法是什么？我应该只对每个字符串进行切片IMG\并获取其后面的内容还是使用正则表达式？

我已经针对该特定行尝试过此操作，看看它是否有效，但它不起作用：

string = r"C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\center_2020_02_08_14_16_38_988.jpg,C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\left_2020_02_08_14_16_38_988.jpg,C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\right_2020_02_08_14_16_38_988.jpg,0,0,0,7.918889E-06 "

new_string = string.replace(r"'C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\'", r"'/home/onur/Documents/behavioral-cloning-CARLA/IMG/'", 3)

print(new_string)

这是输出：

C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\center_2020_02_08_14_16_38_988.jpg,C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\left_2020_02_08_14_16_38_988.jpg,C:\Users\a-ozb\Desktop\onur\behavirol-cloning-carla\IMG\right_2020_02_08_14_16_38_988.jpg,0,0,0,7.918889E-06 

我正在尝试在 Hackerrank 上解决这个问题：

我有这个输入：

........#....#..#..#....#...#..#.#.#.#.#.#..#.....
..#..#..#.#....#..#.....#......#..##...........##.
.........#.###.##...#.....##......###............#
....##........#..#.#.#......#...#.##.......##.....
.................###...#.#...#......#.#.#.#.#...#.
.........#.....#...........##....#.#.#.##.....##..
.....#.##............#....#......#..#..#...##.....
.#.......###....#.#..##.##.#...##...#........#...#
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##..#..#........#....#........#...#.#......#.....#
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#.#...#...#.....#....#......##.#.#.........#....#.
.#..........#......##..#....#....#.#.#..#..###....
#.#............#.##..#.##.##......###......#..#..#
.#..#.##...#.#......................#........#....
.....#....#.#..........##.#.#................#....
##............#.#......####...#.........#..##..#..
....#..##..##...#.........##..##....#..#.##...#...
.#........#...#..#...........#.###.....##.....##..
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...#......#..#...........###...............#......
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#.....#.##..#.......###.........#..##..#......##..

70 行，maxTime 为 2244

这是我的策略，但它适用于某些测试用例：

import …

我正在尝试使用在图像顶部添加叠加层cv2.addWeighted(...)，但它会引发以下错误：

dst = cv2.addWeighted(logo, alpha, overlay, 1-alpha, 0)
cv2.error: OpenCV(4.4.0) /tmp/pip-req-build-99ib2vsi/opencv/modules/core/src/arithm.cpp:691: error: (-5:Bad argument) When the input arrays in add/subtract/multiply/divide functions have different types, the output array type must be explicitly specified in function 'arithm_op'

这个错误对我来说没有意义，因为我检查了文档并且我的论点是适当的。这是我的代码。

def overlay(path):
    logo = cv2.imread(path, cv2.IMREAD_UNCHANGED)
    alpha = logo[:, :, 3]

    overlay = np.zeros(logo.shape, dtype=np.uint8)
    overlay[:, :, 2] = alpha
    overlay[:, :, 3] = alpha

    alpha = 0.5

    dst = cv2.addWeighted(logo, alpha, overlay, 1-alpha, 0)

    pil_image = Image.fromarray(dst).convert('RGBA')

    return pil_image

更新

所以覆盖现在可以工作，但存在一些问题。我对我的代码进行了以下更改： …

我有以下地图：

std::map<char, std::pair<int, int> > robots;

如果输入满足某些条件，我将使用此函数来填充地图：

bool World::addRobot(int row, int col, char robot_name) {

    // This if block checks if the desired location is a valid 1 and keeps a track of all the robots already in the grid
    if (map_[row][col] == '1' && robots.find(robot_name) == robots.end()){
        map_[row][col] = robot_name;
        robots.insert(make_pair(robot_name, std::make_pair(row, col)));
    }
    else{std::cout << "Invalid input" << std::endl;}

  return true;
}

每个机器人名称（只是一个字符）都与其位置（行/列坐标）一起保存。在以下函数中，我希望能够检索给定机器人名称的位置对：

std::pair<int, int> World::getRobot(char robot_name) {

    std::pair<int, int> location = robots.find(robot_name);
    return location;
}

但名称location …