小编Kau*_*mar的帖子

我正在尝试使用颤振来学习应用程序开发.在默认的flutter应用程序代码中,我尝试将以下代码更改为

primarySwatch: Colors.blueGrey

primarySwatch: Colors.blueGrey[500]

但这会引发错误

 ??? EXCEPTION CAUGHT BY WIDGETS LIBRARY ????????????????????????????????????????????????????????????
I/flutter ( 4512): The following assertion was thrown building MyApp(dirty):
I/flutter ( 4512): type 'Color' is not a subtype of type 'MaterialColor' of 'primarySwatch' where
I/flutter ( 4512):   Color is from dart:ui
I/flutter ( 4512):   MaterialColor is from package:flutter/src/material/colors.dart
I/flutter ( 4512):   int is from dart:core
I/flutter ( 4512): 
I/flutter ( 4512): Either the assertion indicates an error in the framework itself, or we should provide substantially …

考虑以下情况

class A
{
    X()
    {
        //some code
        Y();
    }
}

class B extends A
{
    Y(){ //some code }
}

如果我创建了一个类的对象B，并且我尝试使用X从它扩展而来A的函数，那么该函数是否有可能X访问Y类的调用对象的函数B。

class A{
     public void aa(B b){}
     public void bb(){}
}

bb()对于我使用的模拟方法doNothing().when(A).bb();。

aa()由于函数有参数，我应该使用什么。

我想在类似于以下内容的 ansible 中运行任务。

#Task in Playbook

    - name : Include tasks 
      block:
      - name: call example.yml
        include_tasks: "example.yml"
        vars:
          my_var: item
        with_items:
        - [1, 2]

# example.yml

- name: Debug.
  debug:
    msg:
    - "my_var: {{ my_var }}"
  with_inventory_hostnames:
    - 'all'

我希望输出my_var在第一次迭代中打印为值 1，在 playbook 中的循环的第二次迭代中打印为 2。但相反，它正在打印主机名

# Output

TASK [proxysql : Debug.] ************************************************************************************************
 [WARNING]: The loop variable 'item' is already in use. You should set the `loop_var` value in the `loop_control` option for the task to something else to …

当我阅读如何在失败时为黄瓜场景添加清理时，我在互联网上得到了这段代码。

After do |s|
  if s.failed?
    #If you are on an iOS Device
        $driver.quit
         sleep(time_for_driver_ready)
    #else
         reset  
  end
end

这是红宝石。我在 java 中工作，有什么方法可以s.failed?在 java 中实现，因为在 java 中，after 方法声明不包含场景变量。

我有一个作为变量传递的地图

dummy = {
  1 = {
    instances = {
      "ip1" = {
        a = "earth"
        b = "hi"
        c = 1
      }
      "ip2" = {
        a = "world"
        b = "hello"
        c = 2
      }
      "ip3" = {
        a = "planet"
        b = "hey"
        c = 3
      }
    }
  }
}

现在我想构建一个地图，如下所示

value = {
  "ip1" = {
    b = "hi"
    c = 1
  }
  "ip2" = {
    b = "hello"
    c = 2
  }
  "ip3" = {
    b …

如何为这段代码编写单元测试

   if (!isVisible()) {
       throw new IllegalStateException("Not in xyz page");
   }
   return this.isAttached(DOT_ID);

如果isVisible()被模拟返回false那么如何编写异常语句的单元测试