鉴于两个文件:
generic/scripts/hello.sh
parent/scripts -> generic/scripts
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parent/scripts/hello.sh从任何位置调用时,我希望(在脚本中)找到父目录的完整路径.在这种情况下parent.
主要问题是在unix 中parent/scripts/..引用generic.另一方面,涉及正则表达式的所有内容都不是通用的,可能容易出错.
解决方案不起作用:
`dirname $0`/..
realpath `dirname $0`/..
readlink -f `dirname $0`/..
`cd *something*/..; pwd`
`perl ... abs_path(...)`
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所有这些都将指向generic而不是parent因为象征性的联系.
涉及正则表达式的所有内容都不具有适应性/通用性,对于更复杂的路径可能会失败...路径中可能还有其他符号链接,你想要祖父,它是一个涉及的目录名..,你通过$ PATH调用它...
而且,我希望它在任何情况下都可以工作,即使它被称为通过$PATH.
这个简单问题的任何简单安全解决方案?我的意思是它毕竟只是获取父目录!
我用过的:
dir=$( dirname $( cd `dirname $0` >/dev/null; pwd ) )
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Dunno如果它是完美的但似乎表现得像预期的那样.
以下列格式给出ES索引中的JSON:
{
"pin": {
"id": 123,
"location": {
"lat": 456,
"lon":-789
}
}
}
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以下内容使文档与id字段匹配:
client.prepareSearch("index_name")
.setTypes("pin")
.setQuery(QueryBuilders.termQuery("id", 123))
.execute()
.actionGet();
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相反,我正在尝试匹配多个字段,即.(location.lat,location.lon).
QueryBuilders.termQuery(); // accepts only a single term
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尝试了一些替代品,但似乎没有任何替代方案,例如:
QueryBuilder queryBuilder = QueryBuilders.boolQuery()
.must(QueryBuilders.termQuery("location.lat", 456))
.must(QueryBuilders.termQuery("location.lon", -789));
client.prepareSearch("index_name")
.setTypes("pin")
.setQuery(queryBuilder)
.execute()
.actionGet();
Run Code Online (Sandbox Code Playgroud) 我想在Jenkins中拥有以下工作流程:
如何才能做到这一点?
我想做点什么:
<div class='row' ng-repeat='row in _.range(0,12)'>
<div id='{{row}}'></div>
</div>
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但在控制器中我尝试:
function SetterForCatanCtrl($scope) {
$scope._ = _;
try {
var tile = document.getElementById('5');
tile.style.backgroundImage = "url('aoeu.png')";
} catch (e) {
alert(e)
}
}
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getElementById 返回null,那么如何使用AngularJS变量设置元素的id?
我做了:
git p4 clone //depot/path/to/project/trunk/@all project
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创建master分支project.现在我想克隆//depot/path/to/project/release到release分支project.怎么做的?
更新:使用--detect-branches也不起作用.它报告它正在更新两个分支(当真正有三个分支时)但git branch报告只有master存在.
我有以下代码:
function TestStats($xhr) {
$xhr(
'GET',
'/test-dashboard/get-projects.json',
angular.bind(this, function(code, response) {
this.projects = response.projects;
this.projects.splice(0, 0, undefined);
}));
this.$watch('project', angular.bind(this, function() {
this.testClassStats = undefined;
if (this.project) {
$xhr(
'GET',
'/test-dashboard/get-test-stats.json?project=' + this.project,
angular.bind(this, function(code, response) {
this.testClassStats = response.testClassStats;
}));
}
}));
};
TestStats.prototype.greet = function(name) {
return "Hello " + name + "!";
};
TestStats.$inject = ['$xhr'];
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以及以下测试:
TestDashboardUnitTest = TestCase("TestDashboardUnitTest");
TestDashboardUnitTest.prototype.testAoeu = function() {
var xhrStub = function(method, url, callback) {
};
var testStats = new TestStats(xhrStub); …Run Code Online (Sandbox Code Playgroud) 我想做的事情如下:
@RunWith(Categories.class)
@Categories.IncludeCategory(Small.class)
@Categories.ExcludeCategory({Manual.class, NonFunctional.class})
@Suite.SuiteClasses(AllTests.class)
public class SmallTests {
}
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但是ExcludeCategories只接受一个类,而不是类数组.
I am trying to set an env variable which I can use to do relative directory chains. I am trying to do it the following way but cant get it to work. How do I do it?
alias sroot="export SROOT="$PWD""
alias drumit="cd $SROOT/abc/def/drumit"
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If I type sroot, it takes the alias but when i type drumit, it gives me an error saying
bash: cd: /abc/def/drumit: No such file or directory
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Looks like when the shell was launched it takes $SROOT …
我有以下代码:
static def getFamilyDependencies(ConfigurationContainer configurations) {
def result = configurations.collect { configuration ->
configuration.allDependencies.findAll { dependency ->
dependency instanceof DefaultProjectDependency
} collect { projectDependency ->
projectDependency.dependencyProject.name
}
} flatten()
result as Set
}
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我想测试一下.到目前为止,我有:
@Test
void shouldGetFamilyDependencies() {
final Project project = ProjectBuilder.builder().build()
final configurations = project.getConfigurations()
configurations.create('configuration0')
configurations.create('configuration1')
configurations.each { configuration ->
println "***************** ${configuration}"
configuration.allDependencies.each {
println "@@@@@@@@@@@@@@@@@ ${it}"
}
}
}
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如何向配置添加依赖项?以下不起作用:
final Project subproject = ProjectBuilder.builder().build()
configurations.configuration0 {
subproject
}
configurations.configuration1 {
allDependencies {
subproject
} …Run Code Online (Sandbox Code Playgroud) 我有以下代码:
JSch jsch = new JSch();
jsch.setKnownHosts(dotSshDir + "/known_hosts");
jsch.addIdentity(dotSshDir + "/id_rsa");
Session session = jsch.getSession(userName, hostname, 22);
session.connect();
ChannelExec channel = (ChannelExec) session.openChannel("exec");
channel.setCommand(command);
channel.setInputStream(null);
channel.setErrStream(System.err);
Reader reader = new InputStreamReader(channel.getInputStream());
char[] buf = new char[1024];
int numRead;
while ((numRead = reader.read(buf)) != -1) {
String readData = String.valueOf(buf, 0, numRead);
result.append(readData);
buf = new char[1024];
}
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它试图从读者那里读取.我该如何解决?我该怎么做才能找到正在发生的事情?