小编Vik*_*ram的帖子

我收到错误java.text.ParseException:Unparseable date

我希望日期格式为dd-MMM-yyyy.我的代码是:

String v_date_str="Sun Mar 06 11:28:16 IST 2011";
        DateFormat formatter;
        formatter = new SimpleDateFormat("dd-MMM-yyyy");
        Date date_temp=null;
        try {
            date_temp = (Date) formatter.parse(v_date_str);
        } catch (ParseException ex) {
            Logger.getLogger(Attendance_Calculation.class.getName()).log(Level.SEVERE, null, ex);
        }
        System.out.println("output: "+date_temp);

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但是,我得到的错误是:

    The log message is null.
java.text.ParseException: Unparseable date: "Sun Mar 06 11:28:16 IST 2011"
        at java.text.DateFormat.parse(DateFormat.java:337)
        at org.fes.pis.jsf.main.Attendance_Calculation.btn_show_pending_appl_action(Attendance_Calculation.java:415)
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
        at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
        at java.lang.reflect.Method.invoke(Method.java:597)
        at com.sun.el.parser.AstValue.invoke(AstValue.java:187)
        at com.sun.el.MethodExpressionImpl.invoke(MethodExpressionImpl.java:297)
        at com.sun.facelets.el.TagMethodExpression.invoke(TagMethodExpression.java:68)
        at javax.faces.event.MethodExpressionActionListener.processAction(MethodExpressionActionListener.java:99)
        at javax.faces.event.ActionEvent.processListener(ActionEvent.java:88)
        at javax.faces.component.UIComponentBase.broadcast(UIComponentBase.java:771)
        at javax.faces.component.UICommand.broadcast(UICommand.java:372)
        at javax.faces.component.UIViewRoot.broadcastEvents(UIViewRoot.java:475)
        at javax.faces.component.UIViewRoot.processApplication(UIViewRoot.java:756)
        at …

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java datetime parsing

Ann*_*nnu

2013 03-02

6
推荐指数

2
解决办法

7万
查看次数

按字母顺序排序Jtree节点

我已经加载了我的JTree来查看我的目录结构,如我的代码和输出图像所示.这里,Tree节点默认按字母顺序排序,但我的另一个要求是我想根据目录名的第二个名称对所有节点进行排序,而不实际重命名目录.我已经在下面列出了我需要对JTree节点进行排序的名称.请给我一些建议.

import java.io.File;
import javax.swing.JFrame;
import javax.swing.JTree;
import javax.swing.event.TreeModelListener;
import javax.swing.tree.TreeModel;
import javax.swing.tree.TreePath;

public class FILE_NAME {
public static void main(String[] args) {
       JFrame frame = new JFrame("My Jtree");

       File root = new File("C:/java");
       JTree tree = new JTree(new FileTreeModel(root));
       frame.setSize(300, 300);
       frame.setVisible(true);
       frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
       frame.add(tree);
       frame.setVisible(true);            
      }
    }

class FileTreeModel implements TreeModel {

protected File root;

public FileTreeModel(File root) {
    this.root = root;
}

@Override
public Object getRoot() {
    return root;
}

@Override
public boolean isLeaf(Object node) {
    return ((File) …

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java swing jtree

Jon*_*ony

2013 01-25

6
推荐指数

2
解决办法

1万
查看次数