我有一个文本文件，其中包含从 1 到 1000 ( numbers.txt) 的所有数字，我有一个可执行文件 ( ex2-1)，当它获取从 1 到 1000 的所有数字时（它将数字作为输入一个一个），它会打印“完成！ ”。当您运行该文件时，您会看到：
please insert 1:
如果您输入 1，它会显示相同但带有 2，如果不是，它将打印“错误输入”并关闭。
我知道如何逐行读取文本文件：
#!/bin/bash
filename='numbers.txt'
while read line; do
echo "$line" #echo is just to show where the number is being saved
done < $filename
但是有什么方法可以重定向，而不是打印到屏幕上，而是转到可执行文件？
我#define在main中使用之前声明了该函数,但我仍然得到:
隐含的函数fakultet声明...
答案应该是6 ...
#include <stdio.h>
#define fakultet(x) ((x)>1?((x)*(fakultet(x-1))):(1))
int main(void) {
printf(fakultet(3));
}
所以,我想把9个数字写入二进制文件,然后从该文件中读取它们并将它们打印到屏幕上,但由于某种原因它不起作用,我无法弄清楚为什么.我试过在互联网上寻找答案,但似乎没有任何帮助.如果有人能指出我的代码中的错误(这可能非常明显,但我是c的新手),我会非常感激.这是代码:
int main()
{
FILE *f;
if(f=fopen("dat", "wb") == NULL){
return 1;
}
int c;
for(int i = 0; i < 9; i++){
c = fwrite(&i, sizeof(int), 1, f);
printf("%d",c); //it prints 0 every single time, as if nothing was written in the file
}
fclose(f);
if(f=fopen("dat", "rb+")==NULL){
return 1;
}
int a;
while(fread(&a, sizeof(int), 1, f)){
printf("%d\n", a);
}
fclose(f);
}
给出这个示例类模板：
\n\ntemplate<typename T>\nclass Stack {\n T * data;\n int size;\n int nextIndex;\npublic:\n Stack(int size = 100);\n Stack(const Stack& stack);\n ~Stack();\n Stack& operator=(const Stack& s);\n void push(const T& t);\n void pop();\n T& top();\n const T& top() const;\n int getSize() const;\n\n class Full {\n };\n class Empty {\n };\n};\n\ntemplate<typename T>\nvoid Stack::push(const T& t) {\n if (nextIndex >= size) {\n throw Full();\n }\n data[nextIndex++] = t;\n}\n\xc2\xa0\ntemplate<typename T>\nvoid Stack::pop() {\n if (nextIndex <= 0) {\n throw Empty();\n }\n nextIndex--;\n} \npush和方法的实现部分可以吗 …
我最近开始研究汇编代码,我正在尝试重新编码一些基本的系统函数来掌握它,我目前仍然在我的0x0上遇到了一个分段错误strchr.
section .text
global strchr
strchr:
xor rax, rax
loop:
cmp BYTE [rdi + rax], 0
jz end
cmp sil, 0
jz end
cmp BYTE [rdi + rax], sil
jz good
inc rax
jmp loop
good:
mov rax, [rdi + rcx]
ret
end:
mov rax, 0
ret
我无法弄清楚如何使用GDB调试它,我遇到的文档非常有限或难以理解.
我在C中使用以下主要测试
extern char *strchr(const char *s, int c);
int main () {
const char str[] = "random.string";
const char ch = '.';
char *ret;
ret = strchr(str, ch);
printf("%s\n", ret); …当我检查homework使用向量的内部值时cout，似乎只返回内部的值homework[0]。有人可以查看我的代码并让我知道我要去哪里了吗？
int main()
{
cout << "Please enter midterm and final: " << endl;
double midterm, gfinal;
cin >> midterm >> gfinal;
cout << "Enter all your homework grades, " << endl;
double x;
cin >> x;
// initing a vector object named homework
vector<double> homework;
// show debug on the vector
while (homework.size() != 3)
homework.push_back(x);
if (homework.size() == 0)
{
cout << endl << "You need to enter at least one number"; …在下面的代码中，什么是
vector<int> avector (arr, arr + sizeof(arr) / sizeof(arr[0]) );
在main()？
vector<int> bubbleSort(vector<int> avector) { //the vector for bubble sort
for (int passnum = avector.size()-1; passnum > 0; passnum -= 1) {
for (int i = 0; i < passnum; i++) {
if (avector[i] > avector[i+1]) {
int temp = avector[i];
avector[i] = avector[i+1];
avector[i+1] = temp;
}
}
}
return avector;
}
int main() {
// Vector initialized using a static array
static const int arr[] = …在C ++中，我们具有类似std::fill或的函数，std::fill_n这些函数是方便的单行方式，以指针数组，向量，std::arrays和其他容器填充值。一些容器也有其自己的fill方法以允许填充恒定值。还有函数std::generate{_n}和std::iota，前者允许使用生成器函数填充元素，后者则用索引填充范围。
我正在寻找的是一种类似的解决方案-最好是一种单线解决方案，并在标准库中定义-该解决方案允许使用某些索引功能填充容器。例如，这将是数组的解决方案：
std::array<int, 100> arr;
for (std::size_t i = 0; i < 100; i++)
arr[i] = f(i);
f(std::size_t i)索引的某些功能在哪里。
有整合的方法吗？
Considering only objects that are movable but non-copyable (e.g., std::thread or std::unique_ptr), I want to transfer the ownership of the resource such an object contains by passing it as an argument to a constructor. I'm comparing two approaches: the constructor taking the object by value vs. by rvalue reference.
As an example with std::thread, consider the following class Value whose constructor takes an std::thread by value:
#include <thread>
#include <utility>
struct Value {
Value(std::thread th): th_(std::move(th)) …c++ ownership-semantics parameter-passing move-semantics c++11
Let's say I have a Human class:
class Human {
public:
bool isFemale;
double height;
Human(bool isFemale, double height) {
this->isFemale = isFemale;
this->height = height;
}
};
and derived classes, such as Female and Male, which implement their own methods. Do I have a way, in C++11, to determine at runtime, depending on the inputs into the Human constructor, which "sub-type" (Male or Female) Human should be? I am putting different behaviour for Male and Female in their respective …