| uId | title | amount | makers | widgets |
1 richard 998 xcorp sprocket
2 swiss 995 ycorp framitz
3 ricky 90 zcorp flobber
4 ricky2 798 xcorp framitz
1 lilrick 390 xcorp sprocket
1 brie 200 mcorp gullywok
1 richard 190 rcorp flumitz
1 brie 490 bcorp sprocket
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等等...
我试图每个只检索3条记录makers,前3条amounts和widgets它们产生
这就是我所拥有的:
SELECT amount, makers FROM (SELECT amount, makers, (SELECT count(*) FROM entry as t2
WHERE t2.amount = t1.amount and t2.makers >= …Run Code Online (Sandbox Code Playgroud)