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如何修复错误“java.lang.IllegalStateException: Layout state should be one of 100 but it is 10”?

我有错误java.lang.IllegalStateException: Layout state should be one of 100 but it is 10。在错误的后续信息下方。

E/AndroidRuntime: FATAL EXCEPTION: main
java.lang.IllegalStateException: Layout state should be one of 100 but it is 10 
at android.support.v7.widget.RecyclerView$State.assertLayoutStep(RecyclerView.java:10053)
at android.support.v7.widget.RecyclerView.dispatchLayoutStep3(RecyclerView.java:3045) 
at android.support.v7.widget.RecyclerView.dispatchLayout(RecyclerView.java:2917)
at android.support.v7.widget.RecyclerView.onLayout(RecyclerView.java:3283) 
at android.view.View.layout(View.java:13916) 
at android.view.ViewGroup.layout(ViewGroup.java:4424) 
at android.support.v4.widget.SwipeRefreshLayout.onLayout(SwipeRefreshLayout.java:596) 
at android.view.View.layout(View.java:13916) 
at android.view.ViewGroup.layout(ViewGroup.java:4424) 
at android.widget.FrameLayout.onLayout(FrameLayout.java:448) 
at android.view.View.layout(View.java:13916) 
at android.view.ViewGroup.layout(ViewGroup.java:4424) 
at android.support.v7.internal.widget.ActionBarOverlayLayout.onLayout(ActionBarOverlayLayout.java:437) 
at android.view.View.layout(View.java:13916) 
at android.view.ViewGroup.layout(ViewGroup.java:4424)
at android.widget.FrameLayout.onLayout(FrameLayout.java:448)
at android.view.View.layout(View.java:13916)
at android.view.ViewGroup.layout(ViewGroup.java:4424)
at android.widget.LinearLayout.setChildFrame(LinearLayout.java:1655)
at android.widget.LinearLayout.layoutVertical(LinearLayout.java:1513)
at android.widget.LinearLayout.onLayout(LinearLayout.java:1426)
at android.view.View.layout(View.java:13916)
at android.view.ViewGroup.layout(ViewGroup.java:4424)
at android.widget.FrameLayout.onLayout(FrameLayout.java:448)
at android.view.View.layout(View.java:13916) …
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android android-recyclerview

6
推荐指数
1
解决办法
5424
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如何在java中解析网页的特定部分?

我正在获取一个网页的主体,其中有一个包含许多行的表,如下所示:

 ...
 ...
 <tbody>
   <tr class="odd">
     <td align="center">08:00</td>
     <td align="center">9.50</td>
     <td>Description of event 1 </td>
     <td align="center">7.80</td>
   </tr>
   <tr class="even">
     <td align="center">09:00</td>
     <td align="center">11.10</td>
     <td>Description of event 2</td>
     <td align="center">27.40</td>
   </tr>
...
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我想从这个表中剪切零件并将其解析为我的对象.我试图使用子字符串,但我不知道文本所需的部分在哪里.此外,我正在寻找正则表达式和不同的解析器.我怎样才能决定我的问题?谢谢

java string parsing substring html-parsing

0
推荐指数
1
解决办法
585
查看次数