我有以下 Python 代码(我想要文本字段中特定数字的第一个匹配项):
import numpy as np
import pandas
data = {'A': [1, 2, 3], 'B': ['bla 4044 bla', 'bla 5022 bla', 'bla 6045 bla']}
df = pandas.DataFrame(data)
def fun_subjectnr(column):
column = str(column)
subjectnr = re.search(r"(\b[4][0-1][0-9][0-9]\b)",column)
subjectnr1 = re.search(r"(\b[2-3|6-8][0-9][0-9][0-5]\b)",column)
subjectnr = np.where(subjectnr == "" and subjectnr1 != "", subjectnr1,
subjectnr)
return subjectnr1
df['C'] = df['B'].apply(fun_subjectnr)
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想要的输出:
A B C
1 bla 4044 bla 4044
2 bla 5022 bla None
3 bla 6045 bla 6045
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它似乎不起作用。当我将 [0] 添加到正则表达式代码时,它会给出一个错误...(subjectnr = re.search(r"(\b[4][0-1][0-9][0-9]\ b)",列)[0]) …
我现在正在寻找很长一段时间,但我无法弄清楚如何替换字符串的实体,其中模式是列中的字符串,并且每行都不同.所以我有这些数据:
var1 var2 var3
"Sentence 1 is exiting, isnt it?" "exiting"
"Sentence 2 is boring, isnt it?" "boring"
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我最终想要这个:
var1 var2 var3
"Sentence 1 is exiting, isnt it?" "exiting" "Sentence 1 is, isnt it?"
"Sentence 2 is boring, isnt it?" "boring" "Sentence 2 is, isnt it?"
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因此,在每一行中都有另一种需要替换的模式.如果我做var3 = gsub(var2,"",var1)我得到一个错误,因为var2不是一个表达式.
谁能帮我?