我正在玩linux网络编程,我写了一个小客户端服务器应用程序,它在客户端和服务器进程之间弹出一条小消息并测量往返时间.我一直看到大约80ms的localhost往返(这是在连接设置之后).这似乎非常高.在Vista上,运行相同代码的同一台机器的时钟频率将大大低于1ms.
关于这种差异可能来自哪里的任何想法?代码非常简单,一端接受,另一端连接,然后通过对等套接字发送/接收.
我只是开始Linux,如果这是一个愚蠢的问题,道歉.
该代码伴随着书实用的Common Lisp包含ASDF文件.如何使用Quicklisp加载此代码?
help(help)说这是pydoc.help的一个包装(有一个扭曲).
扭曲是什么?
$ python
Python 2.7.10 (default, Jul 30 2016, 19:40:32)
[GCC 4.2.1 Compatible Apple LLVM 8.0.0 (clang-800.0.34)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> help(help)
Help on _Helper in module site object:
class _Helper(__builtin__.object)
| Define the builtin 'help'.
| This is a wrapper around pydoc.help (with a twist).
|
| Methods defined here:
|
| __call__(self, *args, **kwds)
|
| __repr__(self)
|
| ----------------------------------------------------------------------
| Data descriptors defined here:
|
| …Run Code Online (Sandbox Code Playgroud) char *str = malloc (14);
sprintf(str, "%s", "one|two|three");
char *token1, *token2, *token3;
char *start = str;
token1 = str;
char *end = strchr (str, '|');
str = end + 1;
end = '\0';
token2 = str;
end = strchr (str, '|');
str = end + 1;
end = '\0';
...
free(start);
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这是免费工作,因为我已经将str中的字节设置为null以便对它进行标记化吗?
由于我对将指针类型内存分配给指针的过分理解,以下原因导致对barrier_create的调用出现总线错误("hi"从不打印).
typedef struct barrier barrier_t;
typedef struct barrier *barrier_p;
barrier_p test_barrier_p;
int main(int argc, char *argv[]) {
barrier_create(*test_barrier_p);
}
int barrier_create(barrier_p *barrier_pointer) {
printf("hi\n");
barrier_p old_barrier, new_barrier;
int count;
old_barrier = (barrier_p) *barrier_pointer;
new_barrier = (barrier_p) malloc(sizeof(*new_barrier));
count = pthread_mutex_init(&new_barrier->lock, NULL);
new_barrier->is_valid = VALID_BARRIER;
new_barrier->counter = 0;
new_barrier->release_flag = 0;
*barrier_pointer = new_barrier;
return HAPPY_HAPPY_JOY_JOY;
}
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我错过了什么或输入错误?
可以像这样定义一个函数:
int foo(int temp1, int temp2 temp3) {
...
}
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特别是temp2和temp3,会导致错误吗?如果没有,整体效果如何?
我是一个初学者,我正在尝试自学Common Lisp,在我的自学期间,我编写了一个函数,我相信它应该适用于递归添加两个参数.但是,该功能总是失败.这是为什么?
(defun sum (n m)
;;;Returns the sum of n and m using recursion
(cond ((eq m 0) n))
(sum (1+ n) (1- m)))
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据我了解,它应该连续加1到n,同时递减m直到m为0,此时递归加法完成
两位玩家都获得相同的随机数!我希望每个玩家得到一个不同的数字,因为他们掷骰子.这是代码:
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
int roll_a_dice(void);
int main(int argc, const char *argv[])
{
int flag;
int answer1 = roll_a_dice();
int answer2 = roll_a_dice();
printf("Die 1 (rolled by player 1): %d\n", answer1);
printf("Die 2 (rolled by player 2): %d\n", answer2);
if (answer1>answer2) {
printf("Player 1 is starting!\n");
flag = 1;
} else {
printf("Player 2 is starting!\n");
flag = 2;
}
printf("Goodbye!\n");
return 0;
}
int roll_a_dice(void)
{
int r;
srand(time(NULL));
r = 1 + rand() % 6; …Run Code Online (Sandbox Code Playgroud)