小编kar*_*jan的帖子

我有一个使用 docker 部署的应用程序，其中一个微服务是 jboss/keycloak 服务器。一切正常，但需要手动检索 keycloak RSA 公钥。是否可以通过 REST API 检索 RSA 公钥？

我正在研究 aws-serverless + react 应用程序。我的问题是使用aws-amplify. 身份验证正常，但不会保留会话。

登录中：

 await Auth.signIn(this.state.email, this.state.password)
            .then(x => {
                console.log(JSON.stringify(x))
            })
            .catch(e => alert(e.message));

回复：

{
    "username": "xxxxx",
    "pool": {
        "userPoolId": "eu-central-1_xxxxx",
        "clientId": "xxxxx",
        "client": {
            "endpoint": "https://cognito-idp.eu-central-1.amazonaws.com/",
            "userAgent": "aws-amplify/0.1.x js"
        },
        "advancedSecurityDataCollectionFlag": true,
        "storage": {
            "loglevel:webpack-dev-server": "INFO"
        }
    },
    "Session": "xxxxx",
    "client": {
        "endpoint": "https://cognito-idp.eu-central-1.amazonaws.com/",
        "userAgent": "aws-amplify/0.1.x js"
    },
    "signInUserSession": null,
    "authenticationFlowType": "USER_SRP_AUTH",
    "storage": {
        "loglevel:webpack-dev-server": "INFO"
    },
    "keyPrefix": "CognitoIdentityServiceProvider.xxxxx",
    "userDataKey": "CognitoIdentityServiceProvider.xxxxx.xx@x.pl.userData",
    "challengeName": "NEW_PASSWORD_REQUIRED",
    "challengeParam": {
        "userAttributes": {
            "email_verified": "true",
            "phone_number_verified": "true",
            "phone_number": …

我在解决以下代码差异时遇到了问题.

  val l1 = List('a', 'b')
  val l2 = List(1, 2, 3, 4)
  val x = l1.flatMap(v1 => l2.map(b => "" +  v1 + b))
  print(x)
//List(a1, a2, a3, a4, b1, b2, b3, b4)

.

  val l1 = List('a', 'b')
  val l2 = List(1, 2, 3, 4)
  val x = l1.flatMap(v1 => l2.map(_ => "" +  v1 + _))
  print(x)
//List(One$$$Lambda$13/398887205@1554909b, One$$$Lambda$13/398887205@6bf256fa, One$$$Lambda$13/398887205@6cd8737, One$$$Lambda$13/398887205@22f71333, One$$$Lambda$13/398887205@13969fbe, One$$$Lambda$13/398887205@6aaa5eb0, One$$$Lambda$13/398887205@3498ed, One$$$Lambda$13/398887205@1a407d53)

不应该_和b表现一样吗？