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用Google Colab写出文件

有没有办法用Google Colab写出文件?例如,如果我使用

import requests
r = requests.get(url)
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这些文件将存储在哪里?可以找到它们吗?同样,我可以通过tensorflow save函数获取我输出的文件吗

saver=tf.Saver(....)
...
path = saver.save(sess, "./my_model.ckpt")
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谢谢!

tensorflow jupyter-notebook google-colaboratory

9
推荐指数
1
解决办法
2万
查看次数

Firebase UI 电子邮件链接登录意图额外为空

以下 3 个函数用于设置电子邮件和其他身份验证检查(按顺序调用)

    private void buildSignInIntentBuilder() {

        ActionCodeSettings actionCodeSettings = ActionCodeSettings.newBuilder()
                        .setAndroidPackageName(getString(R.string.packageName), true, null)
                        .setHandleCodeInApp(true)
                        .setUrl(getString(R.string.dynamic_link_url))
                        .build();

        List<AuthUI.IdpConfig> providers = Arrays.asList(
                new AuthUI.IdpConfig.EmailBuilder()
                        .enableEmailLinkSignIn()
                        .setActionCodeSettings(actionCodeSettings)
                        .build(),
                // new AuthUI.IdpConfig.EmailBuilder().setRequireName(false).build(),
                new AuthUI.IdpConfig.PhoneBuilder()
                        .build(),
                new AuthUI.IdpConfig.GoogleBuilder()
                        .build(),
                new AuthUI.IdpConfig.FacebookBuilder()
                        .build());

        signInIntentBuilder = AuthUI.getInstance()
                .createSignInIntentBuilder()
                .setIsSmartLockEnabled(false)
                .setAvailableProviders(providers)
                .setLogo(R.drawable.icon_forget_me_not_1);
    }

    private void catchEmailLinkSignIn() {
        Log.d(TAG, "Intent: " + getIntent().getExtras());
        if (AuthUI.canHandleIntent(getIntent())) {
            if (getIntent().getExtras() == null) {
                return;
            }

            String link = getIntent().getExtras().getString(ExtraConstants.EMAIL_LINK_SIGN_IN);
            Log.d(TAG, "link: " + link);
            if (link != null) {
                signInIntentBuilder.setEmailLink(link); …
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firebase firebase-authentication firebaseui

6
推荐指数
1
解决办法
205
查看次数