小编San*_*ker的帖子

删除悬停背景下拉引导程序 4

<li class="nav-item active dropdown">
        <a class="nav-link dropdown-toggle" href="#" id="navbarDropdownMenuLink" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
          Dropdown link
        </a>
        <div class="dropdown-menu" aria-labelledby="navbarDropdownMenuLink">
          <a class="dropdown-item" href="#">Action</a>
          <a class="dropdown-item" href="#">Another action</a>
          <a class="dropdown-item" href="#">Something else here</a>
        </div>
      </li>
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我编写了这段代码来使用引导程序创建一个下拉菜单(非常简单),现在我尝试在将鼠标悬停在下拉列表内的项目上时删除背景,但不知何故它们始终保持白色。

这是CSS

.dropdown-menu{
  background-color: transparent;
  border: transparent;
  border: none;
}
.dropdown-menu .dropdown-item > li > a:hover {
  background-image: none;
  background-color: #000;
}
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html css twitter-bootstrap

6
推荐指数
2
解决办法
1万
查看次数

无法确定父/子表之间的连接条件,设置foreign_keys

class Team(db.Model):
    __tablename__ = "Teams"
    id = db.Column(db.Integer, primary_key=True)
    flashscore_id = db.Column(db.String(255), nullable=False, unique=True)
    name = db.Column(db.String(255), nullable=False)

    leagues = db.relationship("League",
                    secondary=league_teams_table)

    standings = db.relationship('Standing', backref='teams', cascade="all,delete")
    fixtures = db.relationship('Fixture', backref='teams', cascade="all,delete")

related_fixtures_table = db.Table('RelatedFixtures',
    db.Column('fixture_id', db.Integer, db.ForeignKey('Fixtures.id')),
    db.Column('related_fixture_id', db.Integer, db.ForeignKey('Fixtures.id')))

class Fixture(db.Model):
    __tablename__ = "Fixtures"
    id = db.Column(db.Integer, primary_key=True)

    home_id = db.Column(db.Integer, db.ForeignKey('Teams.id'),
        nullable=False)
    away_id = db.Column(db.Integer, db.ForeignKey('Teams.id'),
        nullable=False)

    home_ref = db.relationship("Teams", backref="fixture", uselist=False, foreign_keys=[home_id])
    away_ref = db.relationship("Teams", backref="fixture", uselist=False, foreign_keys=[away_id])

    flashscore_id = db.Column(db.String(255), nullable=False, unique=True)
    total_goals = db.Column(db.Integer, …
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python sqlalchemy flask

6
推荐指数
1
解决办法
6387
查看次数

Bulma Steps Extension 不会“踩踏”

我写了以下代码:

<!DOCTYPE html>
<html>
   <head>
      <meta charset="UTF-8">
      <title>Mockup TOPdesk</title>
      <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bulma/0.7.1/css/bulma.css" />
      <link rel="stylesheet" href="https://use.fontawesome.com/releases/v5.3.1/css/all.css" integrity="sha384-mzrmE5qonljUremFsqc01SB46JvROS7bZs3IO2EmfFsd15uHvIt+Y8vEf7N7fWAU" crossorigin="anonymous">
      <link rel="stylesheet" href="css/style.css" />
      <link href="https://fonts.googleapis.com/css?family=Open+Sans:300,400,700" rel="stylesheet">
      <script src="https://code.jquery.com/jquery-3.3.1.slim.js" integrity="sha256-fNXJFIlca05BIO2Y5zh1xrShK3ME+/lYZ0j+ChxX2DA=" crossorigin="anonymous"></script>
      <script src="https://cdn.jsdelivr.net/npm/bulma-steps@2.2.1/dist/js/bulma-steps.js"></script>
      <link rel="stylesheet" href="https://cdn.jsdelivr.net/npm/bulma-steps@2.2.1/dist/css/bulma-steps.min.css">
   </head>
   <body>
      <nav class="navbar is-white">
         <div class="container">
            <div class="navbar-brand">
               <a class="navbar-item brand-text" href="/">
               TOPdesk Admin
               </a>
               <div class="navbar-burger burger" data-target="navMenu">
                  <span></span>
                  <span></span>
                  <span></span>
               </div>
            </div>
            <div id="navMenu" class="navbar-menu">
               <div class="navbar-start">
                  <a class="navbar-item" href="admin.html">
                  Home
                  </a>
               </div>
            </div>
         </div>
      </nav>
      <div class="container">
         <div class="columns">
            <div class="column is-2"> …
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html javascript css bulma

1
推荐指数
1
解决办法
1433
查看次数

如何在Python3中使用sum函数

我试图一次又一次地使用sum函数,但始终收到错误消息。我写了以下代码:

averages["averages_home_goals"] = sum(d['home_goals'] for d in averages.values() if d)
averages["averages_away_goals"] = sum(d['away_goals'] for d in averages.values() if d)
averages["averages_home_conceded"] = sum(d['home_conceded'] for d in averages.values() if d)
averages["averages_away_conceded"] = sum(d['away_conceded'] for d in averages.values() if d)

print(averages)
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averages变量如下所示:

{
    'Belconnen%20United': {
        'home_goals': 4.0,
        'away_goals': 1.0,
        'home_conceded': 0.0,
        'away_conceded': 2.1666666666666665,
    },
    'Canberra%20FC': {
        'home_goals': 1.75,
        'away_goals': 1.8,
        'home_conceded': 2.0,
        'away_conceded': 2.0,
    },
    # More data of a similar structure
}
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运行此命令时,出现以下错误:

TypeError: 'float' object is not subscriptable
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奇怪的是;当我只运行这4行中的一行时,代码可以正常执行(无论哪一行都行)。执行averages["averages_away_goals"] = …

python

0
推荐指数
1
解决办法
75
查看次数

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