我有类似的字符串
AS_!SD 2453iur ks @ d9304-52kasd
我需要得到字符串的2个frumb numbres:
对于那种情况将是:
2453和9304
我在字符串中没有任何分隔符来尝试拆分,并且数字和字符串的长度是可变的,我在WPF中的C#framework 4.0中工作.
谢谢你的帮助,抱歉我的英语不好
我有一个JSON如下:
{
"elements": [
{
"name": "F975CFAF-8FB4-2926-DD56-74CD230D15AF",
"uri": "vm/hpcloud/nova/large",
"parameters": {
"imageUri": "image/hpcloud/nova/ami-00001b03",
"securityGroups": [
"default"
]
},
"metadata": {
"name": "HPCloud Large VM with Ubuntu 10.04 With BitNami WebPack 1.2-0 Nova",
"description": "HPCloud Large VM with Ubuntu 10.04 With BitNami WebPack 1.2-0 Nova"
}
}
]
}
我需要按如下方式操作属性"metadata"(注意附加了新属性):
{
"elements": [
{
"name": "F975CFAF-8FB4-2926-DD56-74CD230D15AF",
"uri": "vm/hpcloud/nova/large",
"parameters": {
"imageUri": "image/hpcloud/nova/ami-00001b03",
"securityGroups": [
"default"
]
},
"metadata": {
"name": "HPCloud Large VM with Ubuntu 10.04 With BitNami WebPack 1.2-0 Nova", …尝试解决此问题.似乎无法将一个num分配给另一个,即使它们实际上是相同的.
无法将类型'Project.Models.Concern.YesNo'隐式转换为'Project.ViewModels.PatientConcernsViewModel.YesNo'.存在显式转换(您是否错过了演员？)
public class Concern
{
public int ConcernID { get; set; }
public YesNo LifeExpectancy { get; set; }
public YesNo CollateralHistoryAvailable { get; set; }
public enum YesNo
{
Yes,
No
}
}
public class PatientConcernsViewModel
{
public int ConcernID { get; set; }
public YesNo LifeExpectancy { get; set; }
public YesNo CollateralHistoryAvailable { get; set; }
public enum YesNo
{
Yes,
No
}
}
// FROM WITHIN MY CONTROLLER
var concern = concernRepository.Find(id);
// load related …示例代码:
Static void main(string[] args) { Class1 c1 = new Class1(); }
Class1 { Class1() { Class2 c2 = new Class2(); } }
Class2 { Class2() { Class1 c1 = new Class1(); } }
上面的代码抛出StackOverFlowException.这里我们以递归方式创建Class1&Class2对象.对象存储在堆中,那么它为什么不抛出HeapOversizedException或someotherException与堆相关？
I have div1 and div2.
If a user is admin I want him to see both of them.
If a user is a simple user, I want him to see only div2.
I used ng-if (beacuse it removes the div completely, and not using display:none)
Is it safe? Can it be intercepted and/or changed by proxy tools and/or chrome developer tools.
I didn't find any info on that.
这是演员代码:
import akka.actor.Actor
class OneActor extends Actor {
def receive = {
//what I should call here to get ?
case _ => println(physicalPaht)
}
}
我可以使用一些"内置"变量:
有任何想法吗？
更新
也是一个self.path.address但它只返回root actor的路径.
我有各种各样的.img-drop-zones文件读取,我希望将它显示在它所放置的特定放置区域的顶部,但我如何得到它？$(this)由于范围不起作用,我该如何通过？
$('.img-drop-zone').on('drop', function(e){
var files = e.originalEvent.dataTransfer.files;
$.each(files, function(index, file){
p.file.read(file, function(content) {
//how can I get the img-drop zone here?
});
})
});
我刚开始学习python.我得到了这样的声明:
output= " name: abc"
log =output.split("=")[1]
这是什么意思[1]？为什么用它？
我需要根据范围变量的长度应用一个类
<div class="col-md-1">
<i class="float-right" ng-class="{'user-online':activeAssignments.length > 0, 'user-offline': activeAssignments.length <= 0}"></i>
</div>
我能做这样的事情,还是有更好的方法呢？
$scope.activeAssignments 在控制器中定义
这里有一点我不明白。map几天前我刚刚了解到的这个函数应该是一个了不起的函数，如果我找到它的用途，它将改变我编写代码的方式。但我仍然看不出它与forEach. 唯一的区别是传递给的函数map用return值替换了当前元素。但是forEach也可以这样做，这意味着它map只是forEach.
MDN 上的示例：
var numbers = [1, 4, 9];
var roots = numbers.map(Math.sqrt);
// roots is now [1, 2, 3], numbers is still [1, 4, 9]
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map
好吧，很酷，我猜？
我可以这样做forEach：
var numbers = [1, 4, 9];
var roots = numbers.forEach(function(el){el=Math.sqrt(el);});
// roots is now [1, 2, 3], numbers is still [1, 4, 9]
其他例子：
var kvArray = [{key:1, value:10}, {key:2, value:20}, {key:3, value: 30}]; …var a = "C:/xyz/ABC/mno/abc.jpg";
我想通过这个可靠的内部:
$('.abc').css( "background-image", "url(a)");
它不工作怎么做？
我试图将base64字节转换为图像.
这是我正在使用的代码:
Private Function Base64ToImage(ByVal base64 As String) As System.Drawing.Image
Dim img As System.Drawing.Image
Dim ms As MemoryStream = New MemoryStream
Dim b1 As String = base64.Replace("_", "/")
Dim b2 As String = base64.Replace("-", "+")
Dim b64 As String = b2.Replace(" ", "+")
Dim bb As String = b64.Substring(0, b64.Length - 3)
Dim b() As Byte
b = Convert.FromBase64String(b64)
ms = New System.IO.MemoryStream(b)
img = System.Drawing.Image.FromStream(ms)
Return img
End Function
这是我得到的错误:
输入不是有效的Base-64字符串,因为它包含非基本64个字符,两个以上的填充字符或填充字符中的非法字符.
问题出在哪儿 ？？