我的 application-dev.yml 文件中有这个：
security:
authentication:
jwt:
# This token must be encoded using Base64 and be at least 256 bits long (you can type `openssl rand -base64 64` on your command line to generate a 512 bits one)
base64-secret: ODNiNWQ5NmY0M2ZiNTg3MDI1YjA2N2Y1OGVjMTY1ZWM3NzkxZTdlN2FiZGYyYzM2ZTljNTVkZGZiZmQzZDFlMTJhODNkMTEyNzM5NmY0MDMzZmI4Y2E2YjFkNzg1MDM2NzAwNDhhZDI1NGVjOGIyMDNlMGU3ZDZhNmQyZDk1YWY=
# Token is valid 24 hours
token-validity-in-seconds: 86400
token-validity-in-seconds-for-remember-me: 2592000
我想解密存储在 postgres 数据库中的用户密码之一，例如：$2a$10$j8S5d7Sr7.8VTOYNviDPOeWX8KcYILUVJBsYV83Y5NtECayypx9lO我该怎么做？
jhipster ×1