小编Ash*_*wal的帖子

我正在尝试将一个分支添加到GitHub上的主分支,并将一个文件夹推送到该分支.

分支的文件夹结构如下 - SocialApp/SourceCode/DevTrunk/SocialApp,所有源代码文件都在最后一个文件夹中.

我使用以下Git命令:

git add *
git commit -m with the message
git push

这只是将第一个文件夹"SocialApp"推送到GitHub并忽略文件夹内的文件夹SourceCode.我该如何解决？

我想在我的笔记本电脑上安装Nachos,笔记本电脑上有Ubuntu 11.04.

代码在C中,所以要构建它我假设我需要交叉编译器.这就是我的问题所在.我使用命令下载了MIPS交叉编译器的源代码

  wget http://mll.csie.ntu.edu.tw/course/os_f08/assignment/mips-decstation.linux-xgcc.gz

我用它解压缩它

tar zxvf mips-decstation.linux-xgcc.gz      

这没关系,但是当我尝试构建nachos操作系统的源代码时,使用make,我得到了这个错误 -

/usr/include/gnu/stubs.h:7:27: fatal error: gnu/stubs-32.h: No such file or directory compilation terminated. make: *** [bitmap.o] Error 1

我试图按照这里给出的指示 - http://mll.csie.ntu.edu.tw/course/os_f08/217.htm,一切正常,除非我尝试使用make.

如何将JAVA_HOMEUbuntu中的值更改为指向Oracle的Java？

应该指向java-6-sun还是java-6-sun-1.6.0.24？

我应该采取哪些步骤来解决错误:

java.net.UnknownHostException: Invalid hostname for server: local

我在Android模拟器中添加了新的虚拟主机名,但结果返回到

 java.net.UnknownHostException virtualhostname at 
  java.net.InetAddress.lookUpHostByName(InetAddress.java:506)

当我在我的PC上键入我的虚拟主机URL时,它可以显示.然后,当我在Emulator上运行并检查Logcat时,如果200,202或错误代码编号,我无法读取或检查HTTP状态.它只是回到了UnknownHostException

我收到错误消息 - 使用未声明的标识符'kUTTypeMovie'

在下面的代码中 -

-(IBAction)selectVideo:(id)sender {
    UIImagePickerController *imagePicker = [[UIImagePickerController alloc] init];
    imagePicker.sourceType = UIImagePickerControllerSourceTypeSavedPhotosAlbum;
    imagePicker.mediaTypes = [[NSArray alloc] initWithObjects:(NSString *)kUTTypeMovie, nil];

    imagePicker.delegate = self;
    [self presentModalViewController:imagePicker animated:YES];
}

它出什么问题了？

我试图看看是否在Ubuntu 11.04上正确配置了ssh:

  ashish@ubuntu:~$ ssh localhost
  ssh: connect to host localhost port 22: Connection refused
  ashish@ubuntu:~$

我该怎么办？

我正在使用OSX 10.8和PyCharm来处理Python开发项目.我已经使用网站上的说明为mac安装了MySQL-python

http://blog.infoentropy.com/MySQL-python_EnvironmentError_mysql_config_not_found

但是,运行该项目会给我这个错误:

django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: dlopen(/Users/ashishagarwal/.python-eggs/MySQL_python-1.2.3-py2.7-macosx-10.6-intel.egg-tmp/_mysql.so, 2): Symbol not found: _mysql_affected_rows
  Referenced from: /Users/ashishagarwal/.python-eggs/MySQL_python-1.2.3-py2.7-macosx-10.6-intel.egg-tmp/_mysql.so
  Expected in: flat namespace
 in /Users/ashishagarwal/.python-eggs/MySQL_python-1.2.3-py2.7-macosx-10.6-intel.egg-tmp/_mysql.so

错误中提到的文件存在于该位置 - /Users/ashishagarwal/.python-eggs/MySQL_python-1.2.3-py2.7-macosx-10.6-intel.egg-tmp/_mysql.so

整个错误消息是 -

/usr/local/bin/python2.7-32 /Users/ashishagarwal/Optimus/MashPotato/backend/mashpotato/manage.py testserver --addrport 8000
Running on development server
Traceback (most recent call last):
  File "/Users/ashishagarwal/Optimus/MashPotato/backend/mashpotato/manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 453, in execute_from_command_line
    utility.execute()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 392, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 272, in fetch_command
    klass = load_command_class(app_name, subcommand)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 77, in load_command_class …

我正在为我的iOS应用程序创建一个标题栏,我在UIView中创建它.我遇到的唯一问题是"主页按钮".按下主页按钮时,需要转到主页,即ViewController.

但是,它看起来并不[self presentViewController:vc animated:NO completion:NULL];适合UIView.

我该如何解决这个问题？

- (void) createTitlebar {

    CGRect titleBarFrame = CGRectMake(0, 0, 320, 55);

    //Create the home button on the top right of the page. When clicked, it will navigate to the home page of the application
    homeButton = [UIButton buttonWithType:UIButtonTypeCustom];
    homeButton.frame = CGRectMake(275, 10, 40, 40);
    [homeButton setTag:1];
    [homeButton setImage:[UIImage imageNamed:@"homeIcon.png"] forState:UIControlStateNormal];
    [homeButton addTarget:self action:@selector(homeButtonPressed:) forControlEvents:UIControlEventTouchUpInside];
    [self addSubview:homeButton];
}

- (IBAction)homeButtonPressed:(id)sender{

    //Transition to the submit button page
    UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil];
    ViewController …

我试图在我的UIView中绘制一个带有黑色边框的透明矩形.

但我的代码创建了一个完全黑色的矩形.到目前为止,这是我的代码:

- (void)drawRect:(CGRect)rect
{
    // Drawing code
    CGRect rectangle = CGRectMake(0, 100, 320, 100);
    CGContextRef context = UIGraphicsGetCurrentContext();
    CGContextSetRGBFillColor(context, 0.0, 0.0, 0.0, 0.5);
    CGContextSetRGBStrokeColor(context, 0.0, 0.0, 0.0, 0.5);
    CGContextFillRect(context, rectangle);

}

- (IBAction)submitButtonClicked:(id)sender{
    NSLog(@"here");
    SuccessOrFailViewController *sfvc = [[SuccessOrFailViewController alloc] init];
    [self presentViewController:sfvc animated:NO completion:NULL];
}

我想在用户点击应用中的提交按钮时打开新页面.但是,这会打开完全黑屏,上面没有任何内容.如何让它打开viewController呢？