有没有办法根据如下条件在 dart 中拆分列表：
[1, 2, 3, 4, 5, 6, 7, 8] (A sample list)
After splitting it based on i % 2 == 0 condition,
it would generate the following two lists:
1) [1, 3, 5, 7]
2) [2, 4, 6, 8]
我知道我可以简单地编写一个循环来遍历所有元素并检查创建两个子列表的条件。但是 Dart 中有没有更短的函数方式呢？提前致谢！
我最近将我的一个 flutter 应用程序的目标 sdk 升级到了 30。之后，拍照就不起作用了。它显示了此链接中提到的错误。
PlatformException（no_available_camera，没有可用于拍照的相机。，null）。
这与 android 11 中的包可见性更改有关。现在第一个链接中有一个解决方案，通过在清单文件中添加以下行来添加查询设备中安装的所有包的权限。
<uses-permission android:name="android.permission.QUERY_ALL_PACKAGES"/>
这对我有用。但query_all_packages 的文档说明如下：
In the vast majority of cases, however, it's possible to fulfill your app's use cases by
interacting with the set of apps that are visible automatically and by declaring the other
apps that your app needs to access in your manifest file. To respect user privacy, your app
should request the smallest amount of package visibility necessary in order for …我有一个数组的问题,并将它们分配给像float这样的值.这是我的代码
System.out.print("Please enter the number of iteration: ");
Scanner scn = new Scanner(System.in);
int inumber = scn.nextInt(); // i get the iteration number
Random rnd = new Random();
float x = -10 + rnd.nextFloat() * 20; // i created random number between 10 and -10
System.out.println("My x = " +x);
float[] xarray = new float[4]; // created my test array
Random arrayrnd = new Random();
for (int i=0;i<inumber;i++) { // created a for loop with that number
for (int j …