小编JEd*_*dot的帖子

我如何转换这一行:

        <user_profil><username>root</username><email>root@foo.bar</email></user_profil>

进入格式化为:

<user_profil>
    <username>root</username>
    <email>root@foo.bar</email>
</user_profil>

使用正则表达式.

另外我不明白为什么$doc->saveHTML() (DOMDocument的一个实例)只将结果作为一行返回.

我正在使用vite、react和typescript然后我收到此错误，有人知道如何解决吗？

这是我的 package.json：

{\n  "name": "",\n  "private": true,\n  "version": "0.0.0",\n  "scripts": {\n    "dev": "vite",\n    "build": "tsc && vite build",\n    "preview": "vite preview"\n  },\n  "dependencies": {\n    "@apollo/client": "^3.7.9",\n    "@composedb/cli": "^0.3.1",\n    "@composedb/client": "^0.3.1",\n    "@didtools/pkh-ethereum": "^0.0.3",\n    "@emotion/react": "^11.9.0",\n    "@emotion/styled": "^11.8.1",\n    "@mui/icons-material": "^5.8.4",\n    "@mui/material": "^5.8.2",\n    "@mui/x-date-pickers": "^5.0.0-alpha.5",\n    "cytoscape": "^3.22.1",\n    "date-fns": "^2.28.0",\n    "did-session": "^1.0.0",\n    "graphql": "^16.6.0",\n    "graphql-tag": "^2.12.6",\n    "moment": "^2.29.4",\n    "react": "^18.0.0",\n    "react-dom": "^18.0.0",\n    "react-router-dom": "^6.3.0",\n    "web3": "^1.8.2"\n  },\n  "devDependencies": {\n    "@types/cytoscape": "^3.19.6",\n    "@types/react": "^18.0.0",\n    "@types/react-dom": "^18.0.0",\n …

我刚刚完成了一个应用程序,一个简单的信使客户端,我正在寻找加密所有数据,无论是3或200个字母的短语.

这类应用程序的最佳算法是什么？此时我正在尝试将3DES与crypto ++一起使用(在VC10上),但填充和其他事情看起来有点困难.

我不熟悉密码学,所以欢迎任何有用的建议.