小编Jam*_*ard的帖子

我正在尝试从Java连接到ElasticSearch,但我只能通过HTTP连接.我不能用TransportClient.ElasticSearch REST API是否有Java客户端包装器？如果是这样,我该如何使用它？

我正在尝试使用Annotations将Spring与Hibernate结合使用,我收到以下错误:

org.springframework.orm.hibernate3.HibernateSystemException : Unknown entity: entities.Bar; nested exception is org.hibernate.MappingException: Unknown entity: entities.Bar

这是我的设置......

我的实体:

package entities;

@Entity    
public class Bar implements Serializable
{
  ...
}

我的豆子:

package blah;

@Repository
@Service("fooService")
@RemotingDestination(channels = { "my-amf" })
public class Foo
{
  protected HibernateTemplate template;

  @Autowired
  public void setSessionFactory(SessionFactory sessionFactory)
  {
    template = new HibernateTemplate(sessionFactory);
  }

  @RemotingInclude
  public void addBar(String name) throws DataAccessException
  {
    Bar bar = new Bar();
    bar.setName(name);
    template.save(bar);
  }

}

我在Spring中启用注释:

<context:annotation-config />
<context:component-scan base-package="blah" />

<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> …

我最近安装了Typesafe Activator到VM.激活器创建的应用程序可以在端口转发后访问,但Activator似乎可以监听localhost.如何将其更改为WAN？

我理解如何在Java中使用动态代理,但我不明白VM是如何实际创建动态代理的.它会生成字节码并加载吗？或者是其他东西？谢谢.

我一直在关注Android 入门文档,当我尝试运行项目时,我得到:

!MESSAGE An internal error occurred during: "Launching HelloAndroid".
!STACK 0
java.lang.NullPointerException
        at com.android.ide.eclipse.adt.internal.launch.AndroidLaunchController.launch(Unknown Source)

该应用程序无法启动.

我正在尝试使用typesafe-platform,当我运行命令激活器ui时,我得到了这个异常:

C:\ activator-0.3.0> activator ui发现以前的进程ID:7552播放服务器进程ID是3828 [info] play - 应用程序启动(Prod)糟糕,无法启动服务器.

org.jboss.netty.channel.ChannelException: Failed to bind to: /127.0.0.1:8888
        at org.jboss.netty.bootstrap.ServerBootstrap.bind(ServerBootstrap.java:272)
        at play.core.server.NettyServer.<init>(NettyServer.scala:129)
        at play.core.server.NettyServer$.createServer(NettyServer.scala:229)
        at play.core.server.NettyServer$$anonfun$main$5.apply(NettyServer.scala:261)
        at play.core.server.NettyServer$$anonfun$main$5.apply(NettyServer.scala:260)
        at scala.Option.map(Option.scala:145)
        at play.core.server.NettyServer$.main(NettyServer.scala:260)
        at activator.UIMain$$anonfun$run$1.apply$mcV$sp(UIMain.scala:107)
        at activator.UIMain$$anonfun$run$1.app`enter code here`ly(UIMain.scala:107)
        at activator.UIMain$$anonfun$run$1.apply(UIMain.scala:107)
        at activator.UIMain.withContextClassloader(UIMain.scala:179)
        at activator.UIMain.run(UIMain.scala:107)
        at activator.UIMain.run(UIMain.scala:86)`enter code here`
        at xsbt.boot.Launch$$anonfun$run$1.apply(Launch.scala:57)
        at xsbt.boot.Launch$.withContextLoader(Launch.scala:77)
        at xsbt.boot.Launch$.run(Launch.scala:57)
        at xsbt.boot.Launch$$anonfun$explicit$1.apply(Launch.scala:45)
        at xsbt.boot.Launch$.launch(Launch.scala:65)
        at xsbt.boot.Launch$.apply(Launch.scala:16)
        at xsbt.boot.Boot$.runImpl(Boot.scala:31)
        at xsbt.boot.Boot$.main(Boot.scala:20)
        at xsbt.boot.Boot.main(Boot.scala)
Caused by: java.net.BindException: Address already in use: bind
        at sun.nio.ch.Net.bind0(Native Method)
        at sun.nio.ch.Net.bind(Net.java:444)
        at sun.nio.ch.Net.bind(Net.java:436) …

如何访问第一位居民的姓名？这是Json文件.以下是什么？

val bigwig = (json \ "residents")(1)..... 


import play.api.libs.json._

val json: JsValue = Json.parse("""
{
  "name" : "Watership Down",
  "location" : {
    "lat" : 51.235685,
    "long" : -1.309197
  },
  "residents" : [ {
    "name" : "Fiver",
    "age" : 4,
    "role" : null
  }, {
    "name" : "Bigwig",
    "age" : 6,
    "role" : "Owsla"
  } ]
}
""")