我使用的是Android Studio,我在那里使用了几个库.
我有:
android-query-full.0.25.10.jar
gson-2.2.4-sources.jar
slide-menu.jar
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我在build.gradle文件中定义了编译整个libs目录,如下所示:
dependencies {
compile 'com.android.support:support-v4:13.0.+'
compile fileTree(dir: 'libs', include: '*.jar')
}
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所有这些都很有效.
现在我想添加另一个库"PullToRefresh"我已经将Res和Src文件夹打包到一个jar文件中,其中包含来自eclipse的源代码(就像我使用SlideMenu.jar一样)并将新创建的jar作为库添加到我的项目旁边所有其他人.
当我尝试构建我的项目时,我从gradle中得到以下错误:
Gradle: : duplicate files during packaging of APK C:\Code\TestProject\Test\build\apk\Endilo-debug-unaligned.apk
Gradle: Execution failed for task ':Endilo:packageDebug'.
> Duplicate files copied in APK res/values/attrs.xml
File 1: C:\Code\TestProject\Test\libs\PullToRefresh.jar
File 2: C:\Code\TestProject\Test\libs\PullToRefresh.jar
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这是非常奇怪的,因为我从同一个jar文件中获取重复项.这里发生了什么!?
我正在使用Visual Studio Test for C++,我正在调试一个特定的测试.Microsoft提供了各种方法来在调试器中运行测试,但没有我真正喜欢的方法.我厌倦了必须找到测试代码,然后按Ctrl+ R,Ctrl+ T(或我讨厌的鼠标).我想要来自任何源代码上下文的Ctrl+ R,Ctrl+ T行为.
有没有办法挂钩F5在调试器中运行选定的测试?
我已经尝试将我的测试项目设置为启动,但这使得F5"无法启动",因为测试是一个DLL.
我有数据库与表联系,我想检查是否有联系某些电话号码.
@Query("SELECT * FROM contact WHERE phone_number = :number")
Flowable<Contact> findByPhoneNumber(int number);
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我有RxJava 2 Composite一次性声明,以检查是否有电话号码联系.
disposable.add(Db.with(context).getContactsDao().findByPhoneNumber(phoneNumber)
.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribeWith(new DisposableSubscriber<Contact>() {
@Override
public void onNext(final Contact contact) {
Log.d("TAG", "phone number fined");
Conversation conversation;
if(contact != null){
conversation = Db.with(context).getConversationsDao().findBySender(contact.getContactId());
if(conversation != null){
conversation.setUpdatedAt(Utils.getDateAndTimeNow());
saveConversation(contact, conversation, context, text, phoneNumber, false);
} else {
conversation = getConversation(contact, contact.getPhoneNumber());
saveConversation(contact, conversation, context, text, phoneNumber, true);
}
} else {
conversation = Db.with(context).getConversationsDao().findByPhone(phoneNumber);
if(conversation != null){
conversation.setUpdatedAt(Utils.getDateAndTimeNow());
saveConversation(contact, conversation, context, text, phoneNumber, false); …Run Code Online (Sandbox Code Playgroud) 在下面发布的代码中,我创建了一个自定义布局的通知.通知的布局包含三个操作按钮.
我现在的问题是,我无法引用代码中的任何按钮,以便我可以根据单击的操作按钮导航到另一个活动.我想要做的Action button 1
是点击何时Activity 1显示,何时Action button 2单击然后Activity 2出现等等.
请告诉我如何在通知的自定义布局中引用视图?
代码:
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// Using RemoteViews to bind custom layouts into Notification
RemoteViews remoteViews = new RemoteViews(getPackageName(), R.layout.layout_notification);
String notification_title = "Notification_Title";
String notification_text = "Notification_Text";
// Open NotificationView Class on Notification Click
Intent intent = new Intent(this, NotificationReply.class);
// Send data to NotificationView Class
intent.putExtra("title", notification_title);
intent.putExtra("text", notification_text);
// …Run Code Online (Sandbox Code Playgroud) java android android-notifications remoteview android-pendingintent
Person.toString()使用Eclipse或IntelliJ IDEA时,有谁知道如何在下面设置断点?
import lombok.AllArgsConstructor;
import lombok.Data;
import lombok.ToString;
@ToString
@AllArgsConstructor
@Data
public class Person {
private String lastName;
private String firstName;
}
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编辑:
如果可能的话,我想只在toString()被叫时停止.
有谁知道如何将InMemoryUploadedFileDjango2中上传文件 ( ) 的内容转换为字符串?
我想知道如何写以下内容convert2string():
uploaded_file = request.FILES['file']
my_xml = convert2string(uploaded_file) # TODO write method(convert to xml string)
obj = MyObject()
parser = MyContentHandler(obj)
xml.sax.parseString(my_xml, parser) # or xml.sax.parse(convertType(uploaded_file), parser)
Run Code Online (Sandbox Code Playgroud) 我需要使用StreamReader读取控制台应用程序上的.txt文件,然后创建一个具有不同名称但内容相同的新文件或备份.问题是我无法弄清楚如何使用第一个文件中的内容放入新文件中.(这是针对学校的事情而且是C#的新手)
using System;
using System.IO;
namespace UserListCopier
{
class Program
{
static void Main()
{
string fineName = "zombieList.txt";
StreamReader reader = new StreamReader(fineName);
int lineNumber = 0;
string line = reader.ReadLine();
while (line != null) {
lineNumber++;
Console.WriteLine("Line {0}: {1}", lineNumber, line);
line = reader.ReadLine();
}
StreamWriter writetext = new StreamWriter("zombieListBackup.txt");
writetext.Close();
System.Console.Read();
reader.Close();
}
}
}
Run Code Online (Sandbox Code Playgroud) 当我尝试使用Postman命中URL时,通过使用我的个人证书可以正常工作。但是当我使用Rest Assured测试用例尝试访问URL时,将抛出上述异常。
配置类别
public class Configuration {
protected SSLConfig config = null;
private static final Logger LOG = LoggerFactory.getLogger(Configuration.class);
@SuppressWarnings("deprecation")
@BeforeClass
public void setKeystore()
{
KeyStore keyStore = null;
KeyStore trustStore = null;
try {
String certPassword = System.getProperty("certPassword");
String certPath = System.getProperty("certPath");
String trustStorePassword = System.getProperty("trustStorePassword");
String trustStorePath = System.getProperty("trustStorePath");
Validate.notNull(certPath, "Path to Certificate on the file system cannot be null");
Validate.notEmpty(certPassword, "Password cannot be empty");
Validate.notNull(trustStorePath, "Path to trustStore on the file system cannot be null");
Validate.notEmpty(trustStorePassword, "TrustStore …Run Code Online (Sandbox Code Playgroud) 我创建了一个可由Maven(mvn clean install exec:exec)运行的可执行Tomcat jar应用程序.Linux上的Ctrl+ 可以停止此应用程序C.但是,它无法在Windows上运行.有谁知道原因和解决方案?
环境:
$ mvn -version
Apache Maven 3.2.2 (45f7c06d68e745d05611f7fd14efb6594181933e; 2014-06-17T22:51:42+09:00)
Maven home: c:\apache-maven-3.2.2
Java version: 1.8.0_121, vendor: Oracle Corporation
Java home: c:\Program Files\Java\jdk1.8.0_121\jre
Default locale: ja_JP, platform encoding: MS932
OS name: "windows 7", version: "6.1", arch: "amd64", family: "dos"
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pom.xml的摘录:
<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat7-maven-plugin</artifactId>
<version>2.1</version>
<executions>
<execution>
<id>tomcat-run</id>
<goals>
<goal>exec-war-only</goal>
</goals>
<phase>package</phase>
<configuration>
<path>/</path>
<enableNaming>true</enableNaming>
<finalName>embtest.jar</finalName>
<charset>utf-8</charset>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<artifactId>maven-war-plugin</artifactId>
<version>2.6</version>
<configuration>
<failOnMissingWebXml>false</failOnMissingWebXml>
<warName>ROOT</warName>
</configuration>
</plugin> …Run Code Online (Sandbox Code Playgroud) 我能够在我的eclipse中运行以下代码,但是当我在flink集群中运行它时,我得到以下错误.谁能指导我这个?
我的代码:
public static void main(String[] args) throws Exception {
/**
* Getting the execution Environment
*/
final StreamExecutionEnvironment env = StreamExecutionEnvironment.getExecutionEnvironment();
Properties properties = new Properties();
properties.setProperty("bootstrap.servers", "11.71.10.13:9092");
properties.setProperty("group.id", "Bitfinex");
Map<String, String> config = new HashMap<>();
config.put("cluster.name", "TRADE-ES");
config.put("bulk.flush.max.actions", "1");
config.put("node.name", "node-1");
List<InetSocketAddress> transportAddresses = new ArrayList<>();
transportAddresses.add(new InetSocketAddress(InetAddress.getByName("19.18.1.55"), 9300));
transportAddresses.add(new InetSocketAddress(InetAddress.getByName("19.18.1.78"), 9300));
/**
* Adding the BitFinex-ETHBTC-Order source to the execution environment
*/
DataStream<String> ethbtc_OrderStream = env.addSource(
new FlinkKafkaConsumer010<String>("BitFinex-ETHBTC-Order", new SimpleStringSchema(), properties),
"Kafka_BitFinex-ETHBTC-Order_Source").setParallelism(1);
ethbtc_OrderStream.addSink(new BitfinexEthbtcOrderADLSink<String>()).name("BitfinexEthbtcOrderADLSink")
.setParallelism(10);
ethbtc_OrderStream
.addSink(new …Run Code Online (Sandbox Code Playgroud) java ×4
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django ×1
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tomcat ×1