如何在Java中使用Oracle正则表达式来获得相同的结果,或者如何基于Oracle正则表达式构建Java正则表达式.
甲骨文:
declare
str1 varchar2(50);
begin
str1 := REGEXP_SUBSTR('500 Oracle Parkway, Redwood Shores, CA', ',[^,]+,');
DBMS_OUTPUT.PUT_LINE(str1);
end;
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结果:
, Redwood Shores,
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Java的:
String str1 = null;
Pattern pattern = Pattern.compile(",[^,]+,");
Matcher matcher = pattern.matcher("500 Oracle Parkway, Redwood Shores, CA");
if (matcher.find())
{
str1 = matcher.group(1);
}
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但是这个正则表达式在Java中不起作用.它失败并出现此异常:
Exception in thread "main" java.lang.IndexOutOfBoundsException: No group 1
at java.util.regex.Matcher.group(Matcher.java:538)
at mousemover.Playground.main(Playground.java:16)
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也许有一些算法来映射正则表达式?
我正在尝试按字母顺序对列表进行排序,并将每个名称的第一个字母大写.
当我执行toUpperCase时,它会将每个字母都大写.如果我不使用打印它.map,我会做(topNames2017.substring(0, 1).toUpperCase() + topNames2017.substring(1))工作正常,但我不知道如何在这里应用它
List<String> topNames2017 = Arrays.asList(
"Amelia",
"Olivia",
"emily",
"Isla",
"Ava",
"oliver",
"Jack",
"Charlie",
"harry",
"Jacob"
);
topNames2017
.stream()
.map(String::toUpperCase)
.sorted()
.forEach(System.out::println);
Run Code Online (Sandbox Code Playgroud) 有人可以解释一下为什么这段代码无法编译:
boolean r = (boolean) 0;
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为什么这个编译?
double z = (float) 2.0_0+0___2;
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我不理解写入浮点数后的数字.
在setInterval中调用时,我无法理解函数范围.
当我在setInterval中直接声明一个匿名函数时,如下所示:
let lastEventUUID = "some ID";
const interval = setInterval(async function() {
console.log("lastEventUUID -> " + lastEventUUID);
lastEventUUID = "another ID";
}, 1000);Run Code Online (Sandbox Code Playgroud)
我得到的一切都按预期工作
lastEventUUID -> some ID
lastEventUUID -> another ID
...
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但是当我分开宣布我的功能时
async function myFunc(lastEventUUID) {
console.log("lastEventUUID -> " + lastEventUUID);
lastEventUUID = "another ID";
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并将调用设置为setInterval:
let lastEventUUID = "some ID";
const interval = setInterval(myFunc, 1000, lastEventUUID);
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我lastEventUUID没有在下次通话中更新
lastEventUUID -> some ID
lastEventUUID -> some ID
...
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我在这里错过了什么?
java ×3
boolean ×1
casting ×1
compilation ×1
expression ×1
javascript ×1
oracle ×1
regex ×1
setinterval ×1
string ×1