小编Mur*_*one的帖子

我得到了这个 OCaml 代码：

for x = 0 to 12 do\n    let i = (1 + (x * 3)) in\n    let j = (60 - (x * 5)) in\n    Printf.printf "I=%d J=%d\\n" (i) (j);\ndone;;\n

我把它翻译成 Haskell，但它不起作用：

import Text.Printf\n\nfor list action = mapM_ action list\n\nmain :: IO ()\nmain = do\n    for [0..12] $ \\x -> do\n        let i = (1 + (x * 3))\n            j = (60 - (x * 5)) in\n            printf "I=%d J=%d\\n" i j :: IO …