在此处制作KMeans聚类算法:卡在列表相等性上
#clusters = [[],[]]
prevclusters = list(clusters) # Making a new list using clusters elements.
.....
clusters[loc].append(inputs[i]) # Modifying clusters in a for loop
....
# Now, clusters = [[[1, 1], [1, 2]], [[3, 7], [4, 5], [5, 5]]]
if prevclusters == clusters: # Gives True, why ?