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返回外部功能

Hii我在Biopython中遇到以下错误:'return'在函数外面(文件名..第26行)下面是myfile的代码请帮助

# File Name RandonProteinSequences.py
# standard library
import os
import random

# biopython
from Bio.Seq import Seq
from Bio.Alphabet import IUPAC
from Bio.SeqRecord import SeqRecord
import Bio.writers.SeqRecord.fasta
from Bio import SeqIO
from sys import *

residueList1 = ["C","D","E","F","G","H","I"]
residueList2 = ["A","K","L","M","N","S"]
residueList3 = ["P","Q","R","T","V","W","Y"]
residueList4 = ["C","A","G","U"]
def getProteinSeqRecord(residue, seqcount):
    strSeq = ""
for i in range(0,100,1):
    index = random.randint(0, len(residue)-1)
    strSeq += residue[index]

sequence = Seq(strSeq, IUPAC.IUPACProtein)
seqRec = SeqRecord(sequence, id = 'randSeq' + str(seqcount), description= 'A random …
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python biopython

2
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2
解决办法
3万
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