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如何使用xslt比较和合并两个xml

我想比较两个xmls然后合并它们.例如:

myFile1.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
    <title>Title1</title>
    <description>Description1</description>
    <myid>1</myid>
</data>
<data>
    <title>Title2</title>
    <description>Description2</description>
    <myid>2</myid>
</data>
</catalog>
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myFile2.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
    <title>Title1</title>
    <description>Description1</description>
    <author>Author1</author>
    <date>12/34/5678</date>
    <myid>1</myid>
</data>
<data>
    <author>Author2</author>
    <date>87/65/4321</date>
    <myid>2</myid>
</data>
</catalog>
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期望的输出:

<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<data>
    <title>Title1</title>
    <description>Description1</description>
    <myid>1</myid>
    <author>Author1</author>
    <date>12/34/5678</date>
</data>
<data>
    <title>Title2</title>
    <description>Description2</description>
    <myid>2</myid>
    <author>Author2</author>
    <date>87/65/4321</date>
</data>
</catalog>
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我有一个代码,但它没有按照所需的输出执行.

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="ISO-8859-1" indent="yes"/>
<xsl:variable name="compare" select="'myFile1.xml'"/>
<xsl:variable name="with" select="'myFile2.xml'"/>
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template> …
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xml xslt merge

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