小编Asa*_*bal的帖子

我想通过timePickerDialog获取AM/PM值.我的代码是这样的,它通过timepickerdialog通过用户输入并设置警报.在这里我得到用户输入

datetime = Calendar.getInstance();
new TimePickerDialog(this,this,datetime.get(Calendar.HOUR),datetime.get(Calendar.MINUTE),false).show();

现在当onTimeSet函数调用时,我可以获得用户选择的小时和分钟,但无法获得用户选择的AM/PM值.这是其他代码

public void onTimeSet(TimePicker view, int hourOfDay, int minute) { try { Calendar time = Calendar.getInstance();
String am_pm;

if (datetime.get(Calendar.AM_PM) == Calendar.AM)
    am_pm = "AM";
else if (datetime.get(Calendar.AM_PM) == Calendar.PM)
    am_pm = "PM";

time.set(Calendar.HOUR, hourOfDay);
time.set(Calendar.MINUTE, minute);
//time.set(Calendar.SECOND, 0);
//time.set(Calendar.MILLISECOND, 0);
//time.set(Calendar.AM_PM,datetime.PM);

AlarmManager alarmMgr = (AlarmManager) getSystemService(Context.ALARM_SERVICE);
Intent intent = new Intent(this, AlarmReceiver.class);

PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, intent, 0);      
alarmMgr.set(AlarmManager.RTC_WAKEUP,time.getTimeInMillis(), pendingIntent);
Toast.makeText(this, "Alarm Set", Toast.LENGTH_long);

我在Android应用程序中有一个EditText视图.我的EditText没有将整数值作为输入,但它正在采用所有其他值.以下是我的EditText视图.

<EditText
android:id="@+id/txtSearchItems"
android:layout_width="75dp"
android:layout_height="wrap_content"
android:visibility="visible"
android:hint="Search"
android:textSize="14dp"
android:layout_alignParentLeft="true" 
android:layout_marginTop="2dp"
android:layout_centerHorizontal="true">
</EditText>