我想把我的标记引脚用于此代码:
var map = new GMap2(document.getElementById("map-canvas"));
map.addControl(new GLargeMapControl());
map.addControl(new GMapTypeControl());
map.setCenter(new GLatLng(<?=$lat;?>,<?=$lng;?>), 6);
var point = new GLatLng(<?=$lat;?>,<?=$lng;?>);
var marker = createMarker(point,'Welcome:<b></b><br>Second Info Window with an image<br><img src="http://localhost/gps/user_photo/" width=80 height=80>')
map.addOverlay(marker);
function createMarker(point,html) {
var marker = new GMarker(point);
GEvent.addListener(marker, "click", function() {
marker.openInfoWindowHtml(html);
});
return marker;
}
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我怎样才能做到这一点?????
如何使用此代码在codeigniter中获取多个复选框值
<input type="checkbox" name="assign[]" value="Keyur"> Keyur<br/>
<input type="checkbox" name="assign[]" value="Ritesh"> Ritesh<br/>
<input type="checkbox" name="assign[]" value="Saurabh"> Saurabh<br/>
<input type="checkbox" name="assign[]" value="Maulik"> Maulik<br/>
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在控制器
$data1 = $this->input->post('assign[]');
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我这样做,但不能得到价值,我犯错误????
嘿.我试图在具有相同div id的单个地图上放两个点
但是它不起作用..
代码:
第一,
var map = new GMap2(document.getElementById("map-canvas"));
map.addControl(new GLargeMapControl());
map.addControl(new GMapTypeControl());
map.setCenter(new GLatLng(<?=$lat;?>,<?=$lng;?>), 6);
var point = new GLatLng(<?=$lat;?>,<?=$lng;?>);
var marker = createMarker(point,'Welcome:<b></b><br>Second Info Window with an image<br><img src="http://localhost/gps/user_photo/" width=80 height=80>')
map.addOverlay(marker);
function createMarker(point,html) {
var marker = new GMarker(point);
GEvent.addListener(marker, "click", function() {
marker.openInfoWindowHtml(html);
});
return marker;
}
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第二,
var map = new GMap2(document.getElementById("map-canvas"));
map.addControl(new GLargeMapControl());
map.addControl(new GMapTypeControl());
map.setCenter(new GLatLng(<?=$mylat;?>,<?=$mylng;?>), 6);
var point1 = new GLatLng(<?=$mylat;?>,<?=$mylng;?>);
var marker = createMarker1(point1,'Welcome:<b></b><br>Second Info Window with an image<br><img src="http://localhost/gps/user_photo/" …Run Code Online (Sandbox Code Playgroud) 如何从文件夹中删除多个文件?
code:$query=$this->main_model->get($id);
if($query->num_rows()>0)
{
foreach ($query->result() as $row)
{
unlink("uploads/".$id."/".$row->img_name);
unlink("uploads/".$id."/".$row->img_name_tn);
unlink("uploads/".$id."/".$row->file);
unlink("uploads/".$id."/".$row->file2);
unlink("uploads/".$id."/Thumbs.db");
}
rmdir("uploads/".$id);
}
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这是我使用的代码,但它删除了一个文件。以及如何删除文件夹中的所有文件?
我想创建一个具有项目ID的文件夹然后我必须为该id创建子文件夹,在子文件夹中我添加了两个文件和两个图像....子文件夹的名称是文件名之一没有扩展..我该怎么办?我的代码:function add_sub_project_ok(){
$i=0;
$query = $this->main_model->select_project();
if($query->num_rows()>0)
{
foreach ($query->result() as $row)
{
$data['adv'][$i]['id']=$row->id;
$data['adv'][$i]['p_name']=$row->p_name;
$data['adv'][$i]['d_link']=base_url().'uploads'.$data['adv'][$i]['id'];
$i++;
}
}
$data['p_name']=$this->input->post('pname');
$file_name = $_FILES['image']['name'];
$config['upload_path'] = 'uploads/'.$this->db->insert_id().'/';
$path=$config['upload_path'];
$config['allowed_types'] = 'gif|jpg|jpeg|png|pjpeg';
$config['max_size'] = '750';
$config['max_width'] = '1920';
$config['max_height'] = '1280';
$this->load->library('upload');
foreach ($_FILES as $key => $value)
{
if (!empty($key['name']))
{
$this->upload->initialize($config);
if (!$this->upload->do_upload($key))
{
$errors = $this->upload->display_errors();
// flashMsg($errors);
}
else
{
$temp = $this->_process_pic();
$data['reg']['FK_add_pname_id']=$data['adv'][$i]['id'];
$data['reg']['img_name']=$temp['imagename'];
$data['reg']['img_name_tn']=$temp['thumbnail'];
$data['reg']['ipa']=$_FILES['ipa']['name'];
$data['reg']['plist']=$_FILES['plist']['name'];
$data['reg']['uname']=$_POST['uname'];
$data['reg']['pass']=$_POST['pass'];
$this->main_model->update($data['reg'],$id);
}
}
}
$this->file_upload($data,$id);
}
function file_upload($data,$id) …Run Code Online (Sandbox Code Playgroud)