小编Jew*_*ile的帖子

我写了一个简单的脚本,其范围是:

list=[1,19,46,28 etc...]
dictionary={Joey:(10,2,6,19), Emily: (0,3), etc}

现在我需要找到字典中所有值中至少有一个列表条目的键

示例:19是Joeys值,因此Joey是赢家.

我是怎么做到的(根本没有程序员)

# NodesOfSet = the list

# elementsAndTheirNodes = the dictionary

# loop as many times as the number of key:value entries in the dictionary element:nodes
# simply: loop over all the elements
for i in range (0, len (elementsAndTheirNodes.keys())):

    # there is an indent here (otherwise it wouldnt work anyway)
    # loop over the tuple that serves as the value for each key for a given i-th key:value
    # simply: …

我有一个列表,其中包含多达数千个条目及其值:

lst = [
    [entry1, [value1, value2, value3]],
    [entry2, [value4, value5, value6, value7]],
    ...
]

需要从每个条目的值中弹出除最大值之外的所有内容.

你知道这样做的顺利方式吗？谢谢!