小编MOT*_*DEX的帖子

编辑2

感谢大家的帮助!通过融合答案和其他一些论坛帖子我设法通过以下方式解决:

$string = strip_tags($oNode['div.item-prijs']);
$array = str_split($string,1); 
$arraytotal = ( $array[0] . ',' . $array[1] . $array[2] );
echo $arraytotal;

现在显示正确的价格."7,49"我自动转换为的PHP脚本.

对不起,我不能给更多的问题回答标记.案件结案.

拜托了伙计们

$price = strip_tags($oNode['div.item-prijs']);
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_price;

这将回应7,4,9而不是7,49.但是这段代码是目前为止最好的代码.有人知道如何解决这个问题吗？

好吧,我现在已经坚持了一段时间..

我正在从网站解析数据,我想得到价格,但在网站上没有逗号或价格之间的点.所以它显示像499,4大于99.

当我做:

$price = $oNode['div.item-prijs'];
echo $price;

它将回显499.我希望它添加逗号或4到99之间的点.

我试过了:

$price = $oNode['div.item-prijs'];
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_string;

这将回应:

<,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,7,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,4,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,0,<,s,u,p,>,6,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,6,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,1,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,8,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,2,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,0,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, …

与Java和MySQL相关:按下按钮并检查我的数据库后,ID为25的行仍然存在.为什么？

在QueryManager.java中,一切都已设置并使用数据库.这是在QueryManager.java中:

public void removeGebruiker() {
        String query;
        query = "delete from gebruiker where gebruiker_ID = 25";
    }

在userPanel.java中,我已经可以将用户添加到数据库,但删除不起作用.这是在userPanel.java中:

private void removeUserActionPerformed(java.awt.event.ActionEvent evt) {
        WinkelApplication.getInstance().getQueryManager().removeGebruiker();
        JOptionPane.showMessageDialog(null, "Gebruiker is verwijderd", "Gebruiker", JOptionPane.INFORMATION_MESSAGE);
    }

我想用PHP添加300个空格到文本文件.我不能&nbsp像你已经知道的那样使用(.txt格式,而不是HTML),那么怎么做呢？

因此,您可以看到此代码计算数字,我需要300个空格.

$spaces = 0; // will become 300 spaces

 while ($spaces < 300)
 {
    $spaces++;
 }

并测试我将使用多少个空格

substr_count($spaces, ' ');

谢谢

增加信息:

芯片不支持乘法,只有加法.我应该通过创建一个递归方法mult()来解决这个问题,该方法通过向自身添加x次来执行x和y的乘法运算.它的参数是x和y,它的返回值是x和y的乘积.然后我应该编写方法和main()来调用它.

这是纯粹的逻辑思维,但每当我试着想要做什么时,我都会迷失方向.

我被困在数学部分..我有什么,这不起作用,我知道数学是错的,但我不擅长这个:

public static void mult(int x, int y) {
    x = 0;
    y = 0;
    if (y > 0) {
        for (int i = 0; i < y; i++) {
            x = x * (x * y);
            return mult(x, y);
        }
    }
}

http://jsfiddle.net/afTqb/

每当我单击导航栏上的文本时,它都可以正常工作,但是在文本周围的彩色框上,它不起作用.如何解决这个问题？

谢谢

// navigation
ul 
{
    text-align: left;
    display: inline;
    padding: 15px 4px 17px 0;
    list-style: none;
}
ul li 
{
    font-family: 'century gothic', arial, sans-serif;
    color: #fff;
    display: inline-block;
    margin-right: -4px;
    position: relative;
    padding: 15px 20px;
    background: #4479BA;
    cursor: pointer;
    -webkit-transition: all 0.2s;
    -moz-transition: all 0.2s;
    -ms-transition: all 0.2s;
    -o-transition: all 0.2s;
    transition: all 0.2s;
    -webkit-border-radius: 3px;
    -moz-border-radius: 3px;
    border-radius: 3px;
    border: solid 1px #20538D;
    z-index: 10; 
}
ul li:hover 
{
    background: #3E6FAB;
    color: #fff;
}
ul li …

这对我来说有点混乱,但我必须看看我在x中出现了多少次.因此,如果有人为i输入3而x为4294967295,则应该说0次,但如果有人输入9表示i和4294967295表示x,则应该说3次.

这就是我所拥有的,但输出0表示为0,所以它不起作用..

int main(int argc, char** argv) {
    unsigned int i;
    scanf("%u", &i);
    unsigned int x;
    scanf("%u", &x);
    int output = 0;
    int t = 0;
    while (t < 10) {
        x /= 10;
        if (i == x) {
            output++;
        }
        t++;
    }
    printf("%d", output);
}