小编nvc*_*nvn的帖子

当我说"使用鼠标调整大小"时,我的意思是将指针放在边缘,单击并拖动它将调整大小.
是否有任何JavaFX控件或布局默认情况下这样做？
谢谢!

这是我的代码:

Widget::Widget()
{
    manager = new QNetworkAccessManager(this);
    connect(manager, SIGNAL(finished(QNetworkReply*)),this, SLOT(replyFinished(QNetworkReply*)));

    manager->get(QNetworkRequest(QUrl("http://qt.nokia.com")));
}
void Widget::replyFinished(QNetworkReply* reply)
{
    //some other code here
}

我希望回复会有一些方法,比如getrespnsetext(),但它不是......
可以有人给我看一个例子,我需要的所有东西都是打印出来的响应文本(就像在Javascript Ajax中一样)
感谢你的救命!

我需要编写一个函数来帮助我在某些控制器中执行某些操作,因此我决定创建一个名为Helper的类.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using System.Web.Security;

namespace HocVuiDiary.Helper
{
    public class CookiesHelper
    {
        public void UpdateSubkey(string name, string subkey, string subvalue)
        {
            HttpCookie cookie;
            if (Request.Cookies[name] == null)
            {
                cookie = new HttpCookie(name);
                cookie[subkey] = subvalue;
            }
            else
            {
                cookie = Request.Cookies[name];
                cookie[subkey] = subvalue;
            }
            cookie.Expires = DateTime.Now.AddDays(30);
            Response.Cookies.Add(cookie);
        }
    }
}

问题是我无法再访问请求或响应!
请告诉我正确的方法!

我正在建立一个小型照片库网站,我需要一个能够检测重复图像的功能(不需要100%准确,就像谷歌图像搜索一样).

我正在使用一种非常新的语言(Golang),所以我认为没有任何可用的库.

那么我的出发点是什么？请给我一些关于此的关键字.或者,如果您有任何简单易懂的材料,请与我分享.

我读过关于在SkyDrive中使用Live SDK创建的文件夹位置(在不提关于"边界"参数存在),这里是我的代码:

    WebRequest request = WebRequest.Create("https://apis.live.net/v5.0/folder.77e1a950546be643.77E1A950546BE643!202/files/");
    request.Method = "POST";
    string postData = "{name: \"My example folder\"}";
    byte[] byteArray = Encoding.UTF8.GetBytes(postData);
    request.Headers.Add("Authorization", "Bearer " + access_token);
    request.ContentType = "application/json";
    request.ContentLength = byteArray.Length;

不确定我得到400返回:

{"error":{"code":"request_header_invalid","message":"提供的标题'Content-Type'缺少必需参数'boundary'." }}

我做错了什么？我错过了什么吗？

谢谢你的时间!

我不确定我是否可以在这里提出这个问题,但是:

我有一个我不理解的JavaScript块:

var _0x3a04=["$(3C).4Z(2(){3 o=\x2218\x22,y=\x224r\x22,u=\x223F.\x22,s=\x223v\x22,t=\x22.3D\x22,x=\x223G\x22,w=\x223o\x22,q=\x22.m\x22,p=\x222s\x22,l=q+p,v=\x224H\x22,z=\x223q\x22,r=\x223B\x22;5($(\x22.2s\x22+y+\x22x\x22).1d(\x22a\x22).2M(o)==\x221g://\x22+u+\x22i\x22+s+\x22h\x22+r+\x22s.1D\x22\x26\x26$(\x22.2s\x22+y+\x22x\x22).1d(l).2M(o)==\x221g://\x22+x+\x22r-s\x22+w+\x22.3t\x22+v+\x22t\x22+t+\x22m\x22){1m.3A=(2(){3 a=2(c){3 f=c||{},b=f.1Z||1m.21.2a,g=f.3k||\x221g://1.2q.2g.1D/-2w/2x/2y/2C/2E/2H.2o\x22,d=f.4C||50,e=f.3m||0;(2(j){3 h=j(\x22#1E-2n-3y\x22),k=h.1d(\x22:2m\x22);h.2A(\x27\x3C12 3E=\x222n-1x\x22\x3E\x3C/12\x3E\x27);3 i=j(\x22#2n-1x\x22);h.2F(\x223H\x22,2(){3 m=k.4i();i.4q().15(\x221M...\x22);j.1E({1w:\x221g://\x22+b+\x22/1O/2l/1C?1v=1X-1f-20\x26q=\x22+m+\x22\x262k-22=2B\x22,1s:\x2224\x22,26:\x2227\x22,28:2(I){3 H=I.1B.2e,E,D,G,F,A=\x22\x22;5(H!==1Q){A=\x22\x3C1r\x3E3w 22 1a 3z \x262D;\x22+m+\x22\x262D;\x3C/1r\x3E\x22;A+=\x27\x3Ca 11=\x221U\x22 18=\x22/\x22\x3E\x262j;\x3C/a\x3E\x3C2J\x3E\x27;1a(3 C=0;C\x3CH.16;C++){3 n=46 4a(m,\x224f\x22),G=H[C].1G.$t.1i(n,\x22\x3C25\x3E\x22+m+\x22\x3C/25\x3E\x22);1a(3 B=0;B\x3CH[C].14.16;B++){5(H[C].14[B].1n==\x2229\x22){F=H[C].14[B].18}}5(\x221A\x221f H[C]){E=H[C].1A.$t}17{5(\x221C\x221f H[C]){E=H[C].1C.$t}17{E=\x22\x22}}E=E.1i(/\x3C\x5CS[^\x3E]*\x3E/g,\x22\x22);5(E.16\x3Ee){E=E.1y(0,e)+\x22...\x22}E=E.1i(n,\x22\x3C25\x3E\x22+m+\x22\x3C/25\x3E\x22);5(\x222f$1H\x221f H[C]){D=H[C].2f$1H.1w.1i(/\x5C/s[0-9]+\x5C-c/g,\x22/s\x22+d+\x22-c\x22)}17{D=g}A+=\x27\x3C7\x3E\x3Ca 18=\x22\x27+F+\x27\x22 1K=\x221L\x22\x3E\x3C13\x3E\x3C1N 2p=\x22\x27+d+\x27\x22 1b=\x22\x27+d+\x27\x22 1P=\x22\x27+D+\x27\x22/\x3E\x3C/13\x3E\x3Cb\x3E\x27+G+\x22\x3C/b\x3E\x3C/a\x3E\x3Cp\x3E\x22+E+\x22\x3C/p\x3E\x3C/7\x3E\x22}A+=\x22\x3C/2J\x3E\x22;i.15(A)}17{i.15(\x27\x3Ca 11=\x221U\x22 18=\x22/\x22\x3E\x262j;\x3C/a\x3E\x3C1h\x3E1R 1x!\x3C/1h\x3E\x27)}},1S:2(){i.15(\x27\x3Ca 11=\x221U\x22 18=\x22/\x22\x3E\x262j;\x3C/a\x3E\x3C1h\x3E1T 4p 1B.\x3C/1h\x3E\x27)}});1j 1t});h.2F(\x224s\x22,\x22.1U\x22,2(){i.4x();1j 1t})})(1c)};1j 2(b){a(b)}})();1m.4D=(2(){3 a=2(A){3 d=A||{},h=d.1Z||1m.21.2a,n=d.4G||8,g=d.3f||\x22#3g\x22,e=d.3h||3i,c=d.3j||1W,f=d.3l||4,b=d.3n||2G,m=d.3p||1Y,j=d.3r||1t,k=d.3s||\x222I\x22,i=d.3u||\x221g://1.2q.2g.1D/-2w/2x/2y/2C/2E/2H.2o\x22;$.1E({1w:\x221g://\x22+h+\x22/1O/2l/2h?1v=1X-1f-20\x262k-22=\x22+n+\x22\x22,1s:\x2224\x22,26:\x2227\x22,28:2(G){3 I,B,H,K,M,J,D=\x22\x22,L=G.1B.2e;5(L!==1Q){5(j){D=\x22\x3C1e 11=\x272U 2V\x27\x3E\x22}17{D=\x22\x3C1e 11=\x272V\x27\x3E\x22}1a(3 F=0;F\x3CL.16;F++){1a(3 E=0;E\x3CL[F].14.16;E++){5(L[F].14[E].1n==\x2229\x22){I=L[F].14[E].18;1q}}1a(3 C=0;C\x3CL[F].14.16;C++){5(L[F].14[C].1n==\x222Y\x22\x26\x26L[F].14[C].1s==\x222m/15\x22){H=L[F].14[C].1G.30(\x22 \x22)[0];1q}}5(\x221A\x221f L[F]){K=L[F].1A.$t}17{5(\x221C\x221f L[F]){K=L[F].1C.$t}17{K=\x22\x22}}5(\x222f$1H\x221f L[F]){M=L[F].2f$1H.1w.1i(/\x5C/s[0-9]+\x5C-c/g,\x22/s\x22+e+\x22-c\x22)}17{M=i}K=K.1i(/\x3C\x5CS[^\x3E]*\x3E/g,\x22\x22);5(K.16\x3Ec){K=K.1y(0,c)+\x22...\x22}B=L[F].1G.$t;J=L[F].31.$t.1y(0,10),J=J.1i(/-/g,\x22/\x22);D+=\x27\x3C7\x3E\x3C12 11=\x2247\x22\x3E\x3Ca 18=\x22\x27+I+\x27\x22 1K=\x221L\x22\x3E\x3C13\x3E\x3C1N 1v=\x22\x27+B+\x27\x221P=\x22\x27+M+\x27\x22/\x3E\x3C/13\x3E\x3C/a\x3E\x3C/12\x3E\x3C12 11=\x2248\x22\x3E\x3C1r\x3E\x3Ca 18=\x22\x27+I+\x27\x22 1K=\x221L\x22\x3E\x27+B+\x27\x3C/a\x3E\x3C/1r\x3E\x3C12 11=\x2236\x22\x3E\x3C13 11=\x2237\x22\x3E\x27+J+\x27\x3C/13\x3E\x3C13 11=\x223a\x22\x3E\x27+H+\x22 \x22+k+\x27\x3C/13\x3E\x3C/12\x3E\x3C/12\x3E\x3C12 11=\x224o\x22\x3E\x27+K+\x22\x3C/12\x3E\x3C/7\x3E\x22}D+=\x22\x3C/1e\x3E\x22;$(g).15(D);(2(N){N.2u.2v=2(O,Q,P){O=O||4;Q=Q||2z;P=P||1Y;1j 19.2b(2(){3 X=N(19),W=1F,V=[],U=O,R=X.1d(\x22\x3E 7:2i\x22).1b(),T=0;2 S(){5(W){3 Y=N(V[U]).1u({1b:0,1o:0}).2K(X);X.1d(\x22\x3E 7:2L\x22).1p({1o:0},P,2(){Y.1p({1b:R},P).1p({1o:1},P);N(19).23()});U++;5(U\x3E=T){U=0}}2N(S,Q)}X.1d(\x22\x3E 7\x22).2b(2(){V.2O(\x22\x3C7\x3E\x22+N(19).15()+\x22\x3C/7\x3E\x22)});T=V.16;X.2P(\x27\x3C12 11=\x223x\x22 /\x3E\x27).2Q().1u({1b:R*O});X.1d(\x22\x3E 7\x22).2R(\x22:2S(\x22+(O-1)+\x22)\x22).23();X.1k(\x221J\x22,2(){W=1t}).1k(\x221I\x22,2(){W=1F});S()})}})(1c);1c(2(){5(j){1c(\x221e.2U\x22).2v(f,b,m).1k(\x222W\x22,2(){1c(19).2c(\x221J\x22)}).1k(\x222X\x22,2(){1c(19).2c(\x221I\x22)})}})}17{$(g).15(\x22\x3C13\x3E1R 1x!\x3C/13\x3E\x22)}},1S:2(){$(g).15(\x22\x3C1h\x3E1T 1M 2r!\x3C/1h\x3E\x22)}})};1j 2(b){a(b)}})();1m.3I=(2(){3 a=2(B){3 …

这是我的JS代码,(如果我删除标题选项,它可以正常工作).

$http.get(env.apiURL()+'/banks', {
    headers: {
        'Authorization': 'Bearer '+localStorageService.get('access_token')
    }
})

这是请求:

OPTIONS /banks HTTP/1.1
Host: localhost:8080
Connection: keep-alive
Access-Control-Request-Method: GET
Origin: http://localhost:8081
User-Agent: Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/33.0.1750.146 Safari/537.36
Access-Control-Request-Headers: accept, authorization
Accept: */*
Referer: http://localhost:8081/
Accept-Encoding: gzip,deflate,sdch
Accept-Language: en-US,en;q=0.8,vi;q=0.6

和回应:

HTTP/1.1 404 Not Found
Access-Control-Allow-Headers: Accept, Content-Type, Content-Length, Accept-Encoding, X-CSRF-Token, Authorization
Access-Control-Allow-Methods: POST, GET, OPTIONS, PUT, DELETE
Access-Control-Allow-Origin: http://localhost:8081
Content-Type: text/plain; charset=utf-8
Date: Mon, 17 Mar 2014 11:05:20 GMT
Content-Length: 19

我添加了Accept和Authorization …

我正在尝试使用 Amazon SES API 发送原始电子邮件以包含附件。
SES 响应 400 状态代码，我不确定我做错了什么，这是响应：

<ErrorResponse xmlns="http://ses.amazonaws.com/doc/2010-12-01/">
  <Error>
    <Type>Sender</Type>
    <Code>InvalidParameterValue</Code>
    <Message>Duplicate header 'Content-Type'.</Message>
  </Error>
  <RequestId>ad8cb17c-a8a0-11e4-8898-8924aa87abfa</RequestId>
</ErrorResponse>

该请求已签名并与其他请求一起正常工作，因此我认为它必须只是我的电子邮件消息问题。这是我的消息数据：

Cc: my-verified-email-1@gmail.com
Subject: Hello testing email hahahahaha
Mime-Version: 1.0
Date: 30 Jan 15 23:54 +0700
Content-Type: multipart/mixed; boundary=7f1a313ee430f85a8b054f085ae67abd6ee9c52aa8d056e7f7e19c6e2887
From: my-verified-email-2@gmail.com
To: my-verified-email-3@gmail.com
--7f1a313ee430f85a8b054f085ae67abd6ee9c52aa8d056e7f7e19c6e2887
Content-Type: text/html; charset=UTF-8
Content-Transfer-Encoding: quoted-printable

Hello <b>testing email</b> with some =E4=B8=96=E7=95=8C and Vi=E1=BB=87t ng=
=E1=BB=AF.
--7f1a313ee430f85a8b054f085ae67abd6ee9c52aa8d056e7f7e19c6e2887
Content-Type: text/plain; charset=utf-8; name="test1.txt"
Content-Transfer-Encoding: base64
Content-Disposition: attachment; filename="test1.txt"

dGVzdGluZyBzdHJpbmcgd2l0aCBWaeG7h3Qgbmfhu68K
--7f1a313ee430f85a8b054f085ae67abd6ee9c52aa8d056e7f7e19c6e2887--

我想在 App Engine 上部署一些模块。现在我让他们通过一个简单的 REST API 相互“交谈”。
我想知道是否有任何类型的“本地地址”可以使用而不是 *.appspot.com 公共域？

如果没有可用的，两个模块之间通信的快速协议/方法是什么，不包括共享相同的数据库和内存缓存？

我不确定这个关于Qt或C++的问题,我只是这两个的新手!
我有一个简单的Qt应用程序,有一个MainWindow和Hello类,如下所示:

hello.h

#ifndef HELLO_H
#define HELLO_H

#include <QWidget>
#include "mainwindow.h"

class Hello : public QWidget
{
    Q_OBJECT
public:
    explicit Hello(MainWindow *parent = 0);

signals:

public slots:

};

#endif // HELLO_H

heloo.cpp

#include "hello.h"

Hello::Hello(MainWindow *parent) :
    QWidget(parent)
{
//nothing here yet
}

mainwindow.h

#ifndef MAINWINDOW_H
#define MAINWINDOW_H

#include <QtGui/QMainWindow>
#include "hello.h"

class MainWindow : public QMainWindow
{
    Q_OBJECT

public:
    MainWindow(QWidget *parent = 0);
    ~MainWindow();

private:
    Hello* hi;
};

#endif // MAINWINDOW_H

mainwindows.cpp

#include "mainwindow.h"

MainWindow::MainWindow(QWidget …