快速学习课程.我一直在读,构造函数(Python中的def init)应该只设置已分配的变量,计算的实例属性应该通过属性设置.此外,使用@property优先于Java风格的getter/setter.
好的,但是我见过的每个例子都只设置了一个属性.假设我有一个具有三个复杂属性的对象需要计算,查询等.你如何表示多个@property getter,setter,deleters？以下是另一篇文章的示例:
class C(object):
def __init__(self):
self._x = None
@property
def x(self):
"""I'm the 'x' property."""
return self._x
@x.setter
def x(self, value):
self._x = value
@x.deleter
def x(self):
del self._x
因此,如果我有三个实例变量是基于其他一些属性的计算值,它是否会像这样
class C(object):
def __init__(self):
self._x = None
@property
def x(self):
"""I'm the 'x' property."""
return self._x
@x.setter
def x(self, value):
self._x = value
@x.deleter
def x(self):
del self._x
@property
def y(self):
"""I'm the 'y' property.""" …当我点击链接时,任何人都可以建议为什么这段代码不起作用.
链接在ifame中,我希望链接切换主页面中的菜单.
<script>
$(document).ready(function() {
quickout = 0;
$("#scrollsetting").click(function(){
if (quickout==0){
window.parent.document.getElementById('quickmenu').show(300);
quickout = 1;
} else {
window.parent.document.getElementById('quickmenu').hide(300);
menuout=0;
}
})
});
</script>
//这是我的java代码
public class HomeActivity extends AppCompatActivity implements NavigationView.OnNavigationItemSelectedListener {
BottomNavigationView bottomNavigationView;
NavigationView navigationView;
private BottomNavigationView.OnNavigationItemSelectedListener mOnNavigationItemSelectedListener = new BottomNavigationView.OnNavigationItemSelectedListener() {
@Override
public boolean onNavigationItemSelected(@NonNull final MenuItem item) {
switch (item.getItemId()) {
case R.id.home:
HomeFragment homeFragment=new HomeFragment();
android.support.v4.app.FragmentTransaction fragmentTransaction=getSupportFragmentManager().beginTransaction();
fragmentTransaction.replace(R.id.frameLayout,homeFragment).commit();
return true;
case R.id.navigation_stylist:
StylistFragment stylistsFragment=new StylistFragment();
android.support.v4.app.FragmentTransaction fragmentTransaction1=getSupportFragmentManager().beginTransaction();
fragmentTransaction1.replace(R.id.frameLayout,stylistsFragment).commit();
return true;
case R.id.navigation_apps:
MyapptsFragment myaaptsFragment=new MyapptsFragment();
android.support.v4.app.FragmentTransaction fragmentTransaction2=getSupportFragmentManager().beginTransaction();
fragmentTransaction2.replace(R.id.frameLayout,myaaptsFragment).commit();
return true;
case R.id.navigation_tips:
HairtipsFragment hairtipsFragment=new HairtipsFragment();
android.support.v4.app.FragmentTransaction fragmentTransaction3=getSupportFragmentManager().beginTransaction();
fragmentTransaction3.replace(R.id.frameLayout,hairtipsFragment).commit();
return true;
case R.id.navigation_account:
AccountFragment accountFragment=new AccountFragment();
android.support.v4.app.FragmentTransaction fragmentTransaction4=getSupportFragmentManager().beginTransaction();
fragmentTransaction4.replace(R.id.frameLayout,accountFragment).commit();
return …我有一个从Gremlin控制台工作的Gremlin查询
g.V("p1").as("this").out("ContributedTo").in("ContributedTo").where(neq("this")).groupCount()
我想通过Python脚本使用它
from __future__ import print_function # Python 2/3 compatibility
from gremlin_python import statics
from gremlin_python.structure.graph import Graph
from gremlin_python.process.graph_traversal import __
from gremlin_python.process.strategies import *
from gremlin_python.driver.driver_remote_connection import DriverRemoteConnection
graph = Graph()
g = graph.traversal().withRemote(DriverRemoteConnection('wss://neptunedbcluster.neptune.amazonaws.com:8182/gremlin','g'))
g.V('p1').as_('this').out('ContributedTo').in_('ContributedTo').where(__.neq('this')).groupCount()
我得到一个错误：
AttributeError: type object '__' has no attribute 'neq'
我应该如何在Python中表达Gremlin'neq'？
vector < vector <int> > g;
g.resize(n + 1);
我想用 -1 初始化 n + 1 值。我知道如何为单个向量做到这一点，但它是如何在这个向量中发生的。