小编sta*_*low的帖子

#include <iostream>
#include <getopt.h>

#define no_argument 0
#define required_argument 1 
#define optional_argument 2


int main(int argc, char * argv[])
{
  std::cout << "Hello" << std::endl;

  const struct option longopts[] =
  {
    {"version",   no_argument,        0, 'v'},
    {"help",      no_argument,        0, 'h'},
    {"stuff",     required_argument,  0, 's'},
    {0,0,0,0},
  };

  int index;
  int iarg=0;

  //turn off getopt error message
  opterr=1; 

  while(iarg != -1)
  {
    iarg = getopt_long(argc, argv, "svh", longopts, &index);

    switch (iarg)
    {
      case 'h':
        std::cout << "You hit help" << std::endl;
        break;

      case …

函数示例: 调用getThings(amount,place,limit,marginError)

概要: CALL getThings(4, PA, 3, 1.2);

目标的例子:

CREATE PROCEDURE getThings(IN amount X, place VARCHAR(30), lim INT, marginError double)
SELECT place, limit, amount
FROM AREA, PRODUCT
WHERE AREA.place=PRODUCT.place
AND PRODUCT.AREA=place
ORDER BY ABS(AMOUNT-marginError)
LIMIT lim;
END

期望的目标是从存储过程中检索最接近的3个产品(使用MySQL)但是在尝试创建过程时我一直遇到sytax错误.

#!/bin/bash 

/home/someDir/myServer $@

#arguments go as follow: ./server IP SERVICE PORT

port = $@ ?

echo "your port "$port

这不是我想要的:last_arg ="$ {!#}"

Java代码:

      @GET
      @Path("/stop/{id}")
      public void stop(
      @PathParam("id") String id,
      @Context HttpServletRequest request,
      @Context HttpServletResponse response) throws ServletException,
      IOException
      {
        server.stop(id);
      }

Java警告被抛出到控制台:

警告:HTTP GET方法public void com.myPackage.stop(java.lang.String,javax.servlet.http.HttpServletRequest,javax.servlet.http.HttpServletResponse)抛出javax.servlet.ServletException,java.io.IOException,必须返回非void类型.

如何使用Java运行时在SSH中运行多个命令？

命令: ssh user@127.0.0.1'export MYVAR = this/dir/is/cool;/run/my/script/myscript; echo $ MYVAR'

@Test
  public void testSSHcmd() throws Exception
  {
    StringBuilder cmd = new StringBuilder();

    cmd.append("ssh ");
    cmd.append("user@127.0.0.1 ");
    cmd.append("'export ");
    cmd.append("MYVAR=this/dir/is/cool; ");
    cmd.append("/run/my/script/myScript; ");
    cmd.append("echo $MYVAR'");

    Process p = Runtime.getRuntime().exec(cmd.toString());
  }

它自己的命令可以工作,但是当试图从java运行时执行时它不会.有什么建议或意见吗？

create table Machine
(
 Machine_ID int primary key,
 Machine_Name varchar(30)
 Machine_Title varchar(30)
)
create table Part
(
 Part_ID int primary key,
 Part_Name varchar(30),
 Part_Description varchar(30)
)

//How do I make this table below?
create table Machine-Part
(
  Machine_ID int foreign key references (Machine.Machine_ID),
  Part_ID int foreign key references (Part.Part_ID)
  Factory_Note varchar(30);
) 

Mysql抱怨语法有问题？

期望的结果:让表'Machine-Part'使用'Machine_ID'和'Part_ID'作为两个主键(它们都是外键).

例

short size = 1234;
    byte[] payload = {12,43, 55,123, 11, 55};

byte [] shortSize = ByteBuffer.allocate(2).putShort(size).array();
byte[] entirePayload = new byte[shortSize.length+payload.length];   

System.arraycopy(shortSize, 0, entirePayload, 0, 2);
System.arraycopy(payload, 0, entirePayload, 2, payload.length);

这是Java System调用的根本原因吗？

我有以下代码

public class Container<T> {
    private T element;
    private T[] tarray;

    public T getElement() {
        return element;
    }

    public void setElement(T element) {
        this.element = element;
    }

    public void add(T element) {
        tarray[0] = element;
    }

    public void CreateArray(int size) {
        //Can this be cleaned up better?
        tarray = (T[]) new Object[size];
    }

    public T get() {
        return tarray[0];
    }

    public Container(T someElement) {
        this.element = someElement;
    }

    public Container() {
    }

    public static void main(String[] args) {
        Container<String> myContaier1 …

有人可以澄清C#是强类型还是弱类型语言？并解释原因.

如果我有一个被调用的函数concat可以接受任何对象,那么这被认为是弱类型的吗？

function concat(Object stuff)
{
   //do something here to stuff
}

来自关系数据库背景，我发现将用户及其角色分解为规范化表很容易。但是在 mongo 数据库中这样做的习惯方法是什么？

我有的场景

({    "roles" :
    [
        {"role": "user"},
        {"role": "manager"},
        {"role": "admin"}
    ]

    "privileges" :
    [
        {"privilege": "READ"},
        {"privilege": "READ/WRITE"},
        {"privilege": "ALL"}
    ] 

    "users" :
    [
        {"user": "Sammy"},
        {"user": "Tom"},
        {"user": "Fred"},
        {"user": "Zack"}
    ]

    "userPermissions" :
    [
        {"admin": "Sammy"},
        {"manager": "Tom"},
        {"user": "Fred"},
        {"user": "Zack"}
    ]
})

问题：这是在 Mongo 中建模用户角色的合适方法吗？