之情况:
name
列,unique
因此当相同的值到达时,插入不会更改表INSERT INTO IGNORE
当事件发生时,我正在使用迭代来防止破坏INSERT_IGNORE
发生时我得到0我该如何解决这个问题?
Connection con = null;
try
{
Class.forName("com.mysql.jdbc.Driver");
con = DriverManager.getConnection(URL, USERNAME, PASSWORD);
con.setAutoCommit(false);
Statement s1 = (Statement) con.createStatement();
s1.executeUpdate("INSERT IGNORE INTO ORIGIN (ORI_NAME) VALUES(\""
+ d.getOriginName() + "\")");
Statement s2 = (Statement) con.createStatement();
s2.executeUpdate("INSERT IGNORE INTO STOCK (ORI_ID,S_TITLE) VALUES ("
+ "(SELECT ORI_ID FROM ORIGIN WHERE ORI_ID =LAST_INSERT_ID()),\""
+ d.getStockTitle() + "\")");
}
con.commit();
}
catch (Exception e)
{
if (con != null)
try …
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./myscript --ip 192.168.1.1 --port 1985
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或另一种可能的
./myscript --port 1985 --ip 192.168.1.1
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我想允许我的脚本以任何顺序获取一组参数
./myscript a b c d
./myscript d c b a
./myscript b d a c
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诸如此类
是否有任何已知的命令行工具要求JVM查看java程序的内存使用情况和线程转储.像无头的jvisualvm?
我有以下代码:
SELECT * INTO OUTFILE'~/TestInput/Results.csv'
FIELDS TERMINATED BY ','
LINES TERMINATED BY '\n'
FROM Results;
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期望的结果是不断继续追加到Results.csv
我有以下表格
表农场
+---------+--------+-------------------+-----------+------------+
| FARM_ID |Stock_ID| FARM_TITLE | Size | FARM_VALUE |
+---------+--------+-------------------+-----------+------------+
| 2 | 1 | AgriZone | M | 202 |
| 3 | 1 | Cow Mill | L | 11 |
| 4 | 2 | Beef Farm | H | 540 |
| 5 | 2 | CattleOne | M | 1080 |
| 6 | 2 | FarmOne | L | 455 |
| 7 | 3 | Perdue | H | 333 …
Run Code Online (Sandbox Code Playgroud) 我正在解析DatagramSocket中的无符号位.我总共有24位(或3个字节)进入 - 它们是:1个无符号8位整数,后跟16位有符号整数.但java永远不会将有符号的字节存储到字节/字节数组中?当java接收这些值时,你会丢失最后的第8位吗?
DatagramSocket serverSocket = new DatagramSocket(666);
byte[] receiveData = new byte[3]; <--Now at this moment I lost my 8th bit
System.out.println("Binary Server Listing on Port: "+port);
while (true)
{
DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
serverSocket.receive(receivePacket);
byte[] bArray = receivePacket.getData();
byte b = bArray[0];
}
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自从我把它变成一个字节后,我现在失去了第8位吗?是不是我初始化了一个3字节的字节数组?
我正在使用Spring-Jersey3,并且无法弄清楚如何使用Spring bean对RESTFul API进行单元测试
调节器
package com.controller;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;
import com.service.DataSource;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
@Path("test")
@Component
public class SpringController {
@Autowired
private DataSource datasource;
@GET
@Produces(MediaType.TEXT_PLAIN)
public String getHello() {
return new String(datasource.load());
}
}
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服务接口
package com.service;
public interface DataSource {
public String load();
}
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服务实施
package com.service;
import org.springframework.stereotype.Repository;
@Repository
public class DataSourceImpl implements DataSource {
@Override
public String load() {
return "Hello";
}
}
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ResourceRegister.java(泽西资源注册)
package com.component;
import org.glassfish.jersey.server.ResourceConfig;
import com.controller.SpringController; …
Run Code Online (Sandbox Code Playgroud) 我想知道如何在任务发送到卡时显示图形卡能力的百分比.像Gnome的系统监视器一样.
此外,如何获取设备参数以根据其硬件规格计算百分比
如何nvidia-smi -a
获得利用率?是否有Cuda API要求卡提供此信息?
public static byte[] encryptBytes(byte[] bytes, byte[] key)
{
Cipher cipher = null;
try
{
cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
SecretKeySpec secretKey = new SecretKeySpec(key, "AES");
cipher.init(Cipher.ENCRYPT_MODE, secretKey);
return Base64.encodeBase64(cipher.doFinal(bytes));
}
catch (Exception e)
{
e.printStackTrace();
}
return null;
}
public static byte[] decrpytBytes(byte[] encryptedData, String key)
{
byte[] keyBytes = convertToByteArray(key);
Cipher cipher = null;
try
{
cipher = Cipher.getInstance("AES/ECB/PKCS5PADDING");
SecretKeySpec secretKey = new SecretKeySpec(keyBytes, "AES");
cipher.init(Cipher.DECRYPT_MODE, secretKey);
return cipher.doFinal(Base64.decodeBase64(encryptedData));
}
catch (Exception e)
{
e.printStackTrace();
}
return null;
} …
Run Code Online (Sandbox Code Playgroud) 当我的应用程序使用互联网时,我会调用一个事件.该事件更改了由7帧组成的动画gif.如何让它只循环一次框架?
private void trafficSendingActive(object sender, trafficEventArgs e)
{
txImage.Image = Properties.Resources.blip;
}
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