我想使用Dropdown onchange函数进入html传递值,它在提交按钮中工作正常,但我想使用Dropdown onchange,请帮忙怎么做？
<form method="post" action=" ">
<div align="center">
<select name="value">
<option value="">Show Value</option><br />
<option value="2"> 2 </option><br />
<option value="5"> 5 </option><br />
<option value="10"> 10 </option><br />
<option value="20"> 20 </option><br />
</select>
<input type="submit" name="submit" value="Submit">
</div>
</form>
根据我的了解,我的contact.html文件以及我的_contact.php文件中的所有内容都正常,但出于某种原因,我一直收到Chrome错误消息"...可能已关闭或配置不正确".
这是代码,任何帮助表示赞赏.
联系表格在contact.html中:
<div class="ctext5">
<br />
<form id="form1" name="form1" method="post" action="_contact.php">
<table width="557" border="0" cellspacing="10">
<tr>
<th width="234" scope="row"><label for="firstname">First Name:</label></th>
<td width="545"><input type="text" name="firstname" id="firstname" /></td>
</tr>
<tr>
<th scope="row"><label for="lastname">Last Name:</label></th>
<td><input type="text" name="lastname" id="lastname" /></td>
</tr>
<tr>
</tr>
<tr>
<th scope="row"><label for="_email">E-Mail:</label></th>
<td><input type="text" name="_email" id="_email" /></td>
</tr>
<tr>
<th scope="row"><label for="address">Address:</label></th>
<td><input type="text" name="address" id="address" /></td>
</tr>
<tr>
<th scope="row"><label for="cityzip">City/Zip:</label></th>
<td><input type="text" name="cityzip" id="cityzip" /></td>
</tr>
<tr>
<th scope="row"><label for="phone">Phone #:</label></th>
<td><input type="text" name="phone" …我无法想象如何使这个简单的PHP表单起作用.我做错了什么？
<?php
$first = "firstNumber";
$second = "secondNumber";
$second * $first = "calc";
$calc = "calc";
echo("" . $_GET['$calc'] . "<br />\n");
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8" />
<title></title>
</head>
<body>
<form action="new.php" method="get">
<input type="text" name="firstNumber" id="first">
<input type="text" name="secondNumber" id="second">
<input style="background-color: #0094ff;" type="submit" name="calc" value="???" id="second">
</form>
</body>
</html>