关于如何在Python中重复数组中某个值的任何建议?例如,我想只重复2次array_a:
array_a = [1, 2, 1, 2, 1, 1, 2]
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想要的结果是:我重复每一个2并离开1:
array_a = [1, 2, 2, 1, 2, 2, 1, 1, 2, 2] # only the `2` should be repeated
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我试过numpy,我可以复制整个数组,但不是一定的值.
I used py2app to created an .app bundle of my application, which contains GUI made with tkinter. Everything worked fine.
However, after I sign the app with an entitlement like this
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
<key>com.apple.security.app-sandbox</key>
<true/>
</dict>
</plist>
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the application would crash everytime I open it, with the following report:
Application Specific Information:
dyld: in dlopen()
/Users/jerry/Desktop/Programming/py2app_test/Latin_Helper/Latin_Helper.app/Contents/Resources/lib/python2.7/lib-dynload/zlib.so
Thread 0 Crashed:: Dispatch queue: com.apple.main-thread
0 dyld 0x0000000104d665d0 memcmp + 208
1 …Run Code Online (Sandbox Code Playgroud) 在python3.6中,如果我想遍历一个范围,我可以简单地这样做
for i in range(100): pass
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但是,如果我想异步迭代一个范围,我该怎么办?我不能做
async for i in range(100): pass # Doesn't work
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因为range不是AsyncIterable对象。我能想到的一种解决方案是对范围进行子类化并定义__aiter__方法。但是对我来说感觉真的不是pythonic。有没有什么好的方法/库可以在不定义我自己的类的情况下做到这一点?
我正在尝试测试一个简单的 Python 脚本来发送 macOS 通知:
import UserNotifications
def notif_callback(err):
print("Error in notification callback:",err)
def auth_callback(granted, err):
print("Granted: ",granted,)
print("Error in authorization request: ",err)
content=UserNotifications.UNMutableNotificationContent.alloc().init()
content.setTitle_("Test")
r=UserNotifications.UNNotificationRequest.requestWithIdentifier_content_trigger_('test_notification',content,None)
c=UserNotifications.UNUserNotificationCenter.currentNotificationCenter()
c.requestAuthorizationWithOptions_completionHandler_(0b111111,auth_callback)
c.addNotificationRequest_withCompletionHandler_(r,notif_callback)
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但是,当我尝试运行该程序时,出现以下错误
Granted: False
Error in authorization request: Error Domain=UNErrorDomain Code=1 "Notifications are not allowed for this application" UserInfo={NSLocalizedDescription=Notifications are not allowed for this application}
Error in notification callback: Error Domain=UNErrorDomain Code=1 "Notifications are not allowed for this application" UserInfo={NSLocalizedDescription=Notifications are not allowed for this application}
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我没有看到我的系统有任何通知授权,操作系统似乎自动拒绝了该请求。在系统偏好设置中,Python已被授予所有通知权限。我在这里缺少什么?
从外观来看matplotlib,我猜它正在使用PyQt;但是当我查看它的代码时,我没有发现它根本导入任何GUI库。那么,到底用什么matplotlib来显示图形(例如,调用时的窗口plt.show())?
根据 Python 文档,只有recv()块而不是send(). 我写了以下代码试图制作一个 GUI 数独游戏。我这样做的方式是,即使tkinter正在执行其mainloop. 但是,在测试运行期间,我发现如果我在游戏更新时关闭窗口,则pipe.send()开始阻止(我使用 CPython 分析器发现了这一点。)谁能告诉我原因,如果可能,如何解决这个问题问题?
产生问题:在脚本更新时关闭弹出的窗口。也就是说,在将一些数字打印到控制台时关闭窗口。
我的系统:macOS Sierra 10.12.5
import multiprocessing as mp
import threading
import random
import time
try:
import tkinter as tk # Python3
except ImportError:
import Tkinter as tk # Python2
class VisualizedBoard:
def __init__(self,input_string,pipe):
'''input_string: a string has a length of at least 81 that represent the board from top-left to bottom right.
empty cell is 0'''
self.update_scheduled=False
self.pipe=pipe
# create board …Run Code Online (Sandbox Code Playgroud) 我一直在尝试找出如何使用 Julia 抑制 Jupyter Notebook 中最后一行的输出。特别是当最后一行是赋值时。在带有 Python 内核的 Jupyter Notebook 中,当我这样做时
\nk=5\nRun Code Online (Sandbox Code Playgroud)\n在细胞中,不产生任何输出。然而,在 Julia 中,简单的赋值也会返回一个值,这使得笔记本在视觉上变得多余,并且有时无法使用长返回值来读取。例如,当我有
\nusing Random\nRandom.seed!(0) \nRun Code Online (Sandbox Code Playgroud)\n在单元格中,单元格产生非常长的输出,其中包含几乎不必要的细节。
\nMersenneTwister(UInt32[0x00000000], Random.DSFMT.DSFMT_state(Int32[748398797, 1073523691, -1738140313, 1073664641, -1492392947, 1073490074, -1625281839, 1073254801, 1875112882, 1073717145 \xe2\x80\xa6 943540191, 1073626624, 1091647724, 1073372234, -1273625233, -823628301, 835224507, 991807863, 382, 0]), [0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0 \xe2\x80\xa6 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0], UInt128[0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, 0x00000000000000000000000000000000 \xe2\x80\xa6 0x00000000000000000000000000000000, 0x00000000000000000000000000000000, …Run Code Online (Sandbox Code Playgroud) python ×5
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